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Q:

Some envelops are gums. Some gums are seals. Some seals are adhesives.

Conclusions:

1. Some envelops are seals

2. Some gums are adhesives

3. Some adhesives are seals

4. Some adhesives are gums

A) Only 3	B) Only 1
C) Only 2	D) Only 4

Answer & Explanation Answer: A) Only 3

Explanation:

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Filed Under: Statement and Conclusions
Exam Prep: GRE

Q:

Some boys are men. No man is black

Conclusions:

1. Some boys are not black

2. Some men are boys

A) Only 1 follows	B) Only 2 follows
C) Either 1 or 2 follows	D) Neither 1 nor 2 follows

Answer & Explanation Answer: A) Only 1 follows

Explanation:

Since one premise is negative , the conclusion must be negative. so 2 does not follow and only 1 follows

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Filed Under: Statement and Conclusions
Exam Prep: GRE

Q:

In a simultaneous throw of two dice, what is the probability of getting a total of 7 ?

A) 1/6	B) 1/4
C) 1/20	D) 3/4

Answer & Explanation Answer: A) 1/6

Explanation:

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Filed Under: Probability

Q:

In a simultaneous throw of two dice, what is the probability of getting a doublet ?

A) 1/6	B) 1/3
C) 4/7	D) 4/5

Answer & Explanation Answer: A) 1/6

Explanation:

In a simultaneous throw of two dice, n(S) = 6 x 6 = 36

Let E = event of getting a doublet = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

$P (E) = \frac{n (E)}{n (S)} = \frac{6}{36} = \frac{1}{6}$

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Q:

A man and his wife appear in an interview for two vacancies in the same post. The probability of husband's selection is (1/7) and the probability of wife's selection is (1/5). What is the probability that only one of them is selected ?

A) 2/7	B) 1/7
C) 3/4	D) 4/5

Answer & Explanation Answer: A) 2/7

Explanation:

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Filed Under: Probability

Q:

The dimensions of an open box are 50 cm, 40 cm and 23 cm. Its thickness is 2 cm. If 1 cubic cm of metal used in the box weighs 0.5 gms, find the weight of the box.

A) 8.04kg	B) 8.14kg
C) 8.24kg	D) 9.04kg

Answer & Explanation Answer: A) 8.04kg

Explanation:

Volume of the metal used in the box = External Volume - Internal Volume

= [(50 x 40 x 23) - (44 x 34 x 20)] cu.cm

= 16080 cu.cm

Weight of the metal =[(16080 x 0.5)/1000] kg = 8.04 kg.

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Filed Under: Volume and Surface Area

Q:

What is the cause of thrashing? How does the system detect thrashing? Once it detects thrashing, what can the system do to eliminate this problem?

Answer

Thrashing is caused by under allocation of the minimum number of pages required by a process, forcing it to continuously page fault. The system can detect thrashing by evaluating the level of CPU utilization as compared to the level of multiprogramming. It can be eliminated by reducing the level of multiprogramming.

What_is_the_cause_of_thrashing_How_does_the_system_detect_thrashing_Once_it_detects_thrashing,_what_can_the_system_do_to_eliminate_this_problem1557490890.jpg image

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Subject: Operating Systems

Q:

Four dice are thrown simultaneously. Find the probability that all of them show the same face.

A) 1/216	B) 1/36
C) 2/216	D) 4/216

Answer & Explanation Answer: A) 1/216

Explanation:

The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:

= $6 * 6 * 6 * 6 = 6^{4}$

n(S) = $6^{4}$

Let X be the event that all dice show the same face.

X = { (1,1,1,1,), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}

n(X) = 6

Hence required probability = $\frac{n (X)}{n (S)} = \frac{6}{6^{4}}$ = $\frac{1}{216}$

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Filed Under: Probability

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