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Q:

The ratio of students in a coaching preparing for B.tech and MBA is 4 : 5. The ratio of fees collected from each of B.tech and MBA students is 25 : 16. If the total amount collected from all the students is 1.62 lakh, what is the total amount collected from omly MBA aspirants?

A) Rs. 62,000	B) Rs. 72,000
C) Rs. 82,000	D) None of these

Answer & Explanation Answer: B) Rs. 72,000

Explanation:

The ratio of fees collected from B.Tech : MBA = 4x * 25y : 5x * 16y

= 100xy : 80xy

= 5xy : 4 xy = 5k : 4k

The amount collected only from MBA students = $\frac{4}{9} \times 1.62 l a k h$ = Rs. 72,000

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Filed Under: Ratios and Proportions

Q:

A, B and C have amounts in the ratio of 3 : 4 : 5. First B gives 1/4th to A and 1/4th to C then C gives 1/6th to A. Find the final ratio of amount of A, B and C respectively.

A) 4:3:5	B) 5:4:3
C) 3:4:5	D) 5:2:5

Answer & Explanation Answer: D) 5:2:5

Explanation:

A B C

3x 4x 5x

(3x+x) 2x (5x+x) (B Gives 1/4 to A and 1/4 to C)

=4x 2x 6x

(4x+x) 2x 5x ( C Gives 1/6 to A)

=5x 2x 5x

Therefore, 5 : 2 : 5

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Filed Under: Ratios and Proportions

Q:

For any two numbers m , n ; (m+n) : (m-n) : mn = 7: 1: 60 . Find the value of 1/m : 1/n

A) 4:3	B) 8:7
C) 3:4	D) 7:8

Answer & Explanation Answer: C) 3:4

Explanation:

$\frac{m + n}{m - n} = \frac{7 x}{x} \Rightarrow \frac{m}{n} = \frac{4 x}{3 x}$

Again $m n = 12 x^{2}$

and mn =60x

so, $60 x = 12 x^{2} \Rightarrow x = 5$

=> m= 20 and n= 15

Hence, $\frac{1}{m} : \frac{1}{n} = \frac{1}{20} : \frac{1}{15} = 3 : 4$

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Filed Under: Ratios and Proportions

Q:

The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:

A) 91	B) 910
C) 1001	D) 1911

Answer & Explanation Answer: A) 91

Explanation:

Required number of students = H.C.F of 1001 and 910 = 91

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Filed Under: HCF and LCM

Q:

L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

A) -2	B) -1
C) 1	D) 2

Answer & Explanation Answer: A) -2

Explanation:

H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161.

Let the numbers be a and b . Then , ab= 161.

Now, co-primes with product 161 are (1, 161) and (7, 23).

Since x and y are prime numbers and x >y , we have x=23 and y=7.

Therefore, 3y-x = (3 x 7)-23 = -2

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Filed Under: HCF and LCM

Q:

The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1 : 4 , then the larger of the two numbers is

A) 12	B) 48
C) 84	D) 108

Answer & Explanation Answer: C) 84

Explanation:

Let the numbers be x and 4x. Then, $x \times 4 x = 84 \times 21 \Leftrightarrow x^{2} = \frac{84 \times 21}{4} \Leftrightarrow x = 21$

Hence Larger Number = 4x = 84

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Filed Under: HCF and LCM

Q:

The ratio of two numbers is 3 : 4 and their H.C.F is 4. Their L.C.M is

A) 12	B) 16
C) 24	D) 48

Answer & Explanation Answer: D) 48

Explanation:

Let the numbers be 3x and 4x . Then their H.C.F = x. So, x=4

Therefore, The numbers are 12 and 16

L.C.M of 12 and 16 = 48

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Filed Under: HCF and LCM

Q:

Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are

A) 4, 8, 12	B) 5, 10, 15
C) 10, 20, 30	D) 12, 24, 36

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