9
Q:

# A jar was full with honey. A person  used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated  the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar  solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

 A) 1.25 kg B) 1 kg C) 1.5 kg D) None of these

Explanation:

Let the initial amount of honey in the jar was K, then

$512=K\left&space;(&space;1-\frac{1}{5}&space;\right&space;)^{4}$         $\left&space;[&space;\because&space;\:&space;\:&space;20\:&space;percent=\frac{20}{100}&space;=\frac{1}{5}\right&space;]$

or        $512=&space;K\left&space;(&space;\frac{4}{5}&space;\right&space;)^{4}$

$\Rightarrow\:&space;\:&space;K=\frac{512\times&space;625}{256}$

$\therefore&space;\:&space;\:&space;K=1250$

Hence initially the honey in the jar= 1.25 kg

Q:

Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him ?

 A) 15.84 B) 14.92 C) 13.98 D) 16.38

Explanation:

Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg.

Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25)

=> Total cost of the mixture = Rs. 630

Total kgs of the mixture = 30 + 20 = 50kg

Cost of mixture/kg = 630/50 = 12.6/kg

To make 30% of profit

=> Selling price for manideep = 12.6 + 30% x 12.6

=> Selling price for manideep = 12.6 + 3.78 = 16.38/kg.

3 65
Q:

There are two mixtures of honey and water in which the ratio of honey and water are as 1:3 and 3:1 respectively. Two litres are drawn from first mixture and 3 litres from second mixture, are mixed to form another mixture. What is the ratio of honey and water in it ?

 A) 111:108 B) 11:9 C) 103:72 D) None

Explanation:

From the given data,

The part of honey in the first mixture = 1/4

The part of honey in the second mixture = 3/4

Let the part of honey in the third mixture = x

Then,

1/4             3/4

x

(3/4)-x     x-(1/4)

Given from mixtures 1 & 2 the ratio of mixture taken out is 2 : 3

=> $\inline \fn_jvn \frac{\frac{3}{4}-x}{x-\frac{1}{4}}=\frac{2}{3}$

=> Solving we get the part of honey in the third mixture as 11/20

=> the remaining part of the mixture is water = 9/20

Hence, the ratio of the mixture of honey and water in the third mixture is 11 : 9 .

3 32
Q:

In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?

 A) 2:3 B) 4:3 C) 3:4 D) 3:2

Explanation:

Let he mixes the oils in the ratio = x : y

Then, the cost price of the oils = 60x + 65y

Given selling price = Rs. 68.20

=> Selling price = 68.20(x+y)

Given profit = 10% = SP - CP

=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)

=> 6x + 6.5y = 8.20x + 3.20y

=>2.2x = 3.3y

=> x : y = 3 : 2

6 116
Q:

Milk and water are mixed in a vessel A as 4:1 and in vessel B as 3:2. For vessel C, if one takes equal quantities from A and B, find the ratio of milk to water in C.

 A) 1:9 B) 9:1 C) 3:7 D) 7:3

Explanation:

Ratio of Milk and water in a vessel A is 4 : 1

Ratio of Milk and water in a vessel B is 3 : 2

Ratio of only milk in vessel A = 4 : 5

Ratio of only milk in vessel B = 3 : 5

Let 'x' be the quantity of milk in vessel C

Now as equal quantities are taken out from both vessels A & B

=> 4/5     :     3/5
x
3/5-x          x - 4/5

=> $\inline \fn_jvn \frac{\frac{3}{5}-x}{x-\frac{4}{5}}$  = 1/1 (equal quantities)

=> x = 7/10

Therefore, quantity of milk in vessel C  = 7

=> Water quantity = 10 - 7 = 3

Hence the ratio of milk & water in vessel 3 is 7 : 3

7 271
Q:

In a mixture, the ratio of juice and water is 4 : 3. By adding 6 litre water the ratio of juice and water will be 8 : 7. What is the amount of juice in the original mixture ?

 A) 38 lit B) 96 lit C) 48 lit D) 52 lit

Explanation:

Let the amount of juice and water in original mixture '4x' litre and '3x' litre respectively.

According to given data,

4x/3x+6 =8/7

28x=24x+48

28x–24x=48

4x = 48

x = 12

Amount of juice = 4x = 4×12 = 48 litre.