Sawaal

Quantitative Aptitude - Arithmetic Ability Questions

What is Quantitative Aptitude - Arithmetic Ability?

 

Quantitative Aptitude - Arithmetic Ability test helps measure one's numerical ability, problem solving and mathematical skills. Quantitative aptitude - arithmetic ability is found in almost all the entrance exams, competitive exams and placement exams. Quantitative aptitude questions includes questions ranging from pure numeric calculations to critical arithmetic reasoning. Questions on graph and table reading, percentage analysis, categorization, simple interests and compound interests, clocks, calendars, Areas and volumes, permutations and combinations, logarithms, numbers, percentages, partnerships, odd series, problems on ages, profit and loss, ratio & proportions, stocks &shares, time & distance, time & work and more .

 

Every aspirant giving Quantitative Aptitude Aptitude test tries to solve maximum number of problems with maximum accuracy and speed. In order to solve maximum problems in time one should be thorough with formulas, theorems, squares and cubes, tables and many short cut techniques and most important is to practice as many problems as possible to find yourself some tips and tricks in solving quantitative aptitude - arithmetic ability questions.

 

Wide range of Quantitative Aptitude - Arithmetic Ability questions given here are useful for all kinds of competitive exams like Common Aptitude Test(CAT), MAT, GMAT, IBPS and all bank competitive exams, CSAT, CLAT, SSC Exams, ICET, UPSC, SNAP Test, KPSC, XAT, GRE, Defence, LIC/G IC, Railway exams,TNPSC, University Grants Commission (UGC), Career Aptitude test (IT companies), Government Exams and etc.

Popular Latest Rated
Q:

What was the day on 15th august 1947 ?

A) Friday B) Saturday
C) Sunday D) Thursday
 
Answer & Explanation Answer: A) Friday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

15th_August_1947_day1534219857.jpg image

 

Odd days in 1600 years = 0 

 

Odd days in 300 years = 1

 

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day 

 

Jan.   Feb.   Mar.   Apr.   May.   Jun.   Jul.   Aug 

 

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

 

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days. 

 

 

Hence, as the number of odd days = 5 , given day is Friday.

Report Error

View Answer Report Error Discuss

Filed Under: Calendar - Quantitative Aptitude - Arithmetic Ability
Exam Prep: CAT , Bank Exams , AIEEE , GATE
Job Role: Bank PO , Bank Clerk , IT Trainer

3946 404136
Q:

A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is :

A) 500 B) 1000
C) 1500 D) 2000
 
Answer & Explanation Answer: C) 1500

Explanation:

Let the total profit be Rs. 100.

 

 

 

After paying to charity, A's share  = (95*3/5) = Rs. 57.

 

 

 

If A's share is Rs. 57, total profit = Rs. 100.

 

 

 

If A's share is Rs. 855, total profit  = (100/57*855) = 1500.

Report Error

View Answer Report Error Discuss

Filed Under: Partnership - Quantitative Aptitude - Arithmetic Ability

677 301409
Q:

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was :

A) 2500 B) 2700
C) 2900 D) 3100
 
Answer & Explanation Answer: B) 2700

Explanation:

Total number of votes = 7500 

Given that 20% of Percentage votes were invalid

 => Valid votes = 80%

 Total valid votes = 7500*(80/100) 

1st candidate got 55% of the total valid votes. 

Hence the 2nd candidate should have got 45% of the total valid votes 

=> Valid votes that 2nd candidate got = total valid votes x (45/100) 

7500*(80/100)*(45/100) = 2700

Report Error

View Answer Report Error Discuss

Filed Under: Percentage - Quantitative Aptitude - Arithmetic Ability

2597 300273
Q:

Today is Monday. After 61 days, it will be :

A) Tuesday B) Monday
C) Sunday D) Saturday
 
Answer & Explanation Answer: D) Saturday

Explanation:

Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday.

 

After 61 days, it will be Saturday.

Report Error

View Answer Report Error Discuss

Filed Under: Calendar - Quantitative Aptitude - Arithmetic Ability
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

2590 300091
Q:

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.

A) 360, 160, 200 B) 160, 360, 200
C) 200, 360,160 D) 200,160,300
 
Answer & Explanation Answer: C) 200, 360,160

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

Report Error

View Answer Report Error Discuss

Filed Under: Ratios and Proportions - Quantitative Aptitude - Arithmetic Ability

1856 232268
Q:

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

A) 2:5 B) 3:5
C) 4:5 D) 5:4
 
Answer & Explanation Answer: C) 4:5

Explanation:

Let the third number be x.

Then, first number = 120% of x =120x/100 = 6x/5  


Second number =150% of x = 150x/100 = 3x/2

Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5

Report Error

View Answer Report Error Discuss

Filed Under: Ratios and Proportions - Quantitative Aptitude - Arithmetic Ability

623 217467
Q:

A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved?

A) 1/4 B) 1/2
C) 3/4 D) 7/12
 
Answer & Explanation Answer: C) 3/4

Explanation:

Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event

∴A, B, C are independent events

Now,  P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4

 PA=12, PB=23, PC= 34

∴ P( none  solves the problem) = P(not A) and (not B) and (not C)  

                  = PA∩B∩C 

                  = PAPBPC         ∵ A, B, C are Independent                       

                  =  12×23×34  

                  = 14  

Hence, P(the problem will be solved) = 1 - P(none solves the problem) 

                = 1-14= 3/4

Report Error

View Answer Report Error Discuss

Filed Under: Probability - Quantitative Aptitude - Arithmetic Ability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

951 208775
Q:

Find the odd man out.

2, 5, 10, 17, 26, 37, 50, 64

A) 50 B) 37
C) 26 D) 64
 
Answer & Explanation Answer: D) 64

Explanation:

(1*1)+1 , (2*2)+1 , (3*3)+1 , (4*4)+1 , (5*5)+1 , (6*6)+1 , (7*7)+1 , (8*8)+1

But, 64 is out of pattern.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out - Quantitative Aptitude - Arithmetic Ability

116 165546