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AIEEE Questions

A) Friday | B) Saturday |

C) Sunday | D) Thursday |

Explanation:

**15 Aug, 1947** = (1946 years + Period from 1.1.1947 to 15.8.1947)

**Odd days** in 1600 years = 0

**Odd days** in 300 years = 1

**46 years** = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = **1 odd day **

**Jan. Feb. Mar. Apr. May. Jun. Jul. Aug **

( **31 + 28 + 31 + 30 + 31 + 30 + 31 + 15** ) = 227 days = (32 weeks + 3 days) = **3 odd days.**

**Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days. **

Hence, as the number of **odd days = 5 , given day is Friday.**

A) Tuesday | B) Monday |

C) Sunday | D) Saturday |

Explanation:

Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.

A) BMS | B) LBT |

C) IJF | D) PID |

Explanation:

$L\stackrel{+3}{\to}B\stackrel{-1}{\to}T$

$I\stackrel{+3}{\to}J\stackrel{-1}{\to}F$

$P\stackrel{+2}{\to}I\stackrel{-1}{\to}D$

$B\stackrel{+3}{\to}\stackrel{-1}{\to}S$

Therefore, PID is not in the form of other patterns.

A) 3 | B) 4 |

C) 1 | D) 2 |

Explanation:

4 eyes.

Here in the question, it is asked how many Eyes We have so that means here the person who has asked the question is also including the person who is suppose to give the answer. In a clear understanding, the Conversation is happening between 2 people 1st who asked the question and 2nd to whom it has been asked, which means there are 4 eyes.

A) 1/4 | B) 1/2 |

C) 3/4 | D) 7/12 |

Explanation:

Let A, B, C be the respective events of solving the problem and $\overline{)A},\overline{)B},\overline{)C}$ be the respective events of not solving the problem. Then A, B, C are independent event

$\therefore \overline{)A},\overline{)B},\overline{)C}$ are independent events

Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4

$P\left(\overline{)A}\right)=\frac{1}{2},P\left(\overline{)B}\right)=\frac{2}{3},P\left(\overline{)C}\right)=\frac{3}{4}$

$\therefore $ P( none solves the problem) = P(not A) and (not B) and (not C)

= $P\left(\overline{)A}\cap \overline{)B}\cap \overline{)C}\right)$

= $P\left(\overline{)A}\right)P\left(\overline{)B}\right)P\left(\overline{)C}\right)$ $\left[\because \overline{)A},\overline{)B},\overline{)C}areIndependent\right]$

= $\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}$

= $\frac{1}{4}$

Hence, P(the problem will be solved) = 1 - P(none solves the problem)

= $1-\frac{1}{4}$= **3/4**

A) 062 | B) 602 |

C) 042 | D) 204 |

Explanation:

From all the hints given,

only **042** satisfies and it unlocks the key.

A) 4% of a | B) 6% of a |

C) 8% of a | D) 10% of a |

Explanation:

20% of a = b

=> (20/100) * a = b

b% of 20 =(b/100) x 20 = [(20a/100) / 100] x 20= 4a/100 = 4% of a.

A) 100% | B) 200% |

C) 300% | D) 400% |

Explanation:

Let the C.P be Rs.100 and S.P be Rs.x, Then

The profit is (x-100)

Now the S.P is doubled, then the new S.P is 2x

New profit is (2x-100)

Now as per the given condition;

=> 3(x-100) = 2x-100

By solving, we get

x = 200

Then the Profit percent = (200-100)/100 = 100

Hence the profit percentage is 100%