# Problems on Ages Questions

A) 14 | B) 19 |

C) 33 | D) 38 |

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19.

Son's age 5 years back = (19 - 5) = 14 years

A) 19 | B) 29 |

C) 39 | D) 49 |

Explanation:

Let B's present age = x years. Then, A's present age = (x + 9) years.

(x + 9) + 10 = 2(x - 10)

=> x + 19 = 2x - 20

=> x =39.

A) 12 | B) 13 |

C) 14 | D) 15 |

Explanation:

(A+B) - (B+C) = 12

A - C = 12.

C is younger than A by 12 years.

A) Any two statements are sufficient to give answer | B) Only C is sufficient |

C) All of three statements are necessary to give answer | D) Even using all the three statements answer cannot be found |

Explanation:

From the given statements A, B & C

Let the present age of Teja = P

Raju present age = P + 4

Sita's present age = 2(P + 4)

Average of ages of Sita & Teja = 19

=> (2P + 8 + P)/2 = 19

= 3P + 8 = 38

=> P = 30/3 = 10

Hence, the present age of Teja = P = 10 yrs.

Therefore, by using all the three statements A, B & C we can find the age of Teja.

A) 5 | B) 10 |

C) 15 | D) 20 |

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75 => x = 15