# Quantitative Aptitude - Arithmetic Ability Questions

## What is Quantitative Aptitude - Arithmetic Ability?

Quantitative Aptitude - Arithmetic Ability test helps measure one's numerical ability, problem solving and mathematical skills. Quantitative aptitude - arithmetic ability is found in almost all the entrance exams, competitive exams and placement exams. Quantitative aptitude questions includes questions ranging from pure numeric calculations to critical arithmetic reasoning. Questions on graph and table reading, percentage analysis, categorization, simple interests and compound interests, clocks, calendars, Areas and volumes, permutations and combinations, logarithms, numbers, percentages, partnerships, odd series, problems on ages, profit and loss, ratio & proportions, stocks &shares, time & distance, time & work and more .

Every aspirant giving Quantitative Aptitude Aptitude test tries to solve maximum number of problems with maximum accuracy and speed. In order to solve maximum problems in time one should be thorough with formulas, theorems, squares and cubes, tables and many short cut techniques and most important is to practice as many problems as possible to find yourself some tips and tricks in solving quantitative aptitude - arithmetic ability questions.

Wide range of Quantitative Aptitude - Arithmetic Ability questions given here are useful for all kinds of competitive exams like Common Aptitude Test(CAT), MAT, GMAT, IBPS and all bank competitive exams, CSAT, CLAT, SSC Exams, ICET, UPSC, SNAP Test, KPSC, XAT, GRE, Defence, LIC/G IC, Railway exams,TNPSC, University Grants Commission (UGC), Career Aptitude test (IT companies), Government Exams and etc.

A) 4000 | B) 16000 |

C) 8000 | D) 20000 |

Explanation:

5% of 400000

= 5 x 400000/100

= 20,000

Hence, **5% of 4,00,000 = 20,000**

A) 10 & 12 | B) 10 & 18 |

C) 12 & -18 | D) -12 & 18 |

Explanation:

Given, difference of the squares of two numbers is 180.

= **k ^{2} - l^{2} - 180**

Also, square of the smaller number is 8 times the larger.

= l^{2 }= 8k

Thus,** k ^{2} - 8a - 180 = 0**

k^{2} – 18k + 10k - 180 = 0

→ k(k - 18) + 10(k – 18) = 0

= (k + 10)(k – 18) = 0

→ **k = -10, 18**

Thus, the other number is

**324 - 180 = l**^{2 }

→ Numbers are **12, 18** or **-12, 18.**

A) 8888 | B) 9999 |

C) 9944 | D) 9988 |

Explanation:

To find the largest 4 digit number exactly divisible by 88,

We should divide the largest possible 4 digit number by 88, and if we get any remainder than subtract it from that largest number.

The largest possible 4 digit number is 9999

Now,

88) 9999 (113

88

_______

119

88

_______

319

264

_______

55

_______

Therefore, the largest 4 digit number exactly divisible by 88 is given by

**9999 - 55 = 9944.**

A) 36.333% | B) 33.666% |

C) 33.333% | D) 36.666% |

Explanation:

Cost of 4 mangoes = Rs. 6

Cost of 1 mango = Rs. 6/4 = Rs. 1.5

Now, Selling Price of 4 mangoes = Rs. 4

Selling Price of 1 mango = Rs. 4/4 = Rs. 1.0

- We observe that,
**S.P < C.P**

Hence, the shopkeeper incurs a loss.

Required **loss% = loss/C.P x 100**

Loss = 1.5 - 1 = 0.5

C.P = 1.5

Loss% = (0.5/1.5) x 100

= (5/15) x 100

= 1/3 x 100

= 100/3

**= 33.333%.**

A) 20 | B) 12 |

C) 8 | D) 4 |

Explanation:

Let the required number be 'p'.

From the given data,

p + 12 = 160 x 1/p

=> p + 12 = 160/p

=> p(p + 12) = 160

=> P^2 + 12p - 160 = 0

=> p^2 + 20p - 8p - 160 = 0

=> P(p + 20) - 8(p + 20) = 0

=> (p + 20)(p - 8) = 0

=> p = -20 or p = 8

As, given the number is a natural number, so it can't be negative.

Hence, the required number **p = 8.**

A) 19/6 | B) 32/4 |

C) 16/3 | D) None of the above |

A) 9 | B) 16 |

C) 22 | D) 36 |

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

Hence, the odd man in the series is 22.

A) Rs. 14,400 | B) Rs. 15,600 |

C) Rs. 14,850 | D) Rs. 15,220 |

Explanation:

Let the required Sum = Rs.S

From the given data,

1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]

=> S = Rs. 14,400.