17
Q:

From  a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The  initial amount of wine in the container was:

A) 75 liters B) 100 liters
C) 150 liters D) 120 liters

Answer:   D) 120 liters



Explanation:

Wine (left)Water (added)=343169

 

It means   Wine (left)Wine(initial amount)=343512   343+169 = 512

 

Thus ,       

343x=512x1-15K3

 

 343512=783=1-15k3

 

=> K = 120

Thus the initial amount of wine was 120 liters.

Q:

An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ?

 

A) 113/108 B) 105/103
C) 108/115 D) 103/113
 
Answer & Explanation Answer: B) 105/103

Explanation:

As given equal amounts of alloys are melted, let it be 1 kg.

Required ratio of gold and silver = 513 + 58813 + 38 = 105103.

 

Hence, ratio of gold and silver in the resulting alloy = 105/103.

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4 367
Q:

A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

A) 58 l B) 65 l
C) 50 l D) 62 l
 
Answer & Explanation Answer: C) 50 l

Explanation:

Let the tin contain 5x litres of liquids

5x - 45 x 455x - 45 x 15 + 45 = 25

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

70 - 45 x 15 + 45 

= 50 litres.

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8 1173
Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm B) 50 gm
C) 55 gm D) 60 gm
 
Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper =80100 x 50 = 40 g 

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> 50 + p x 90100 = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

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6 954
Q:

A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

A) 1 : 10 B) 10 : 1
C) 9 : 11 D) 11 : 9
 
Answer & Explanation Answer: A) 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk          ::        Water

  6.4                         0

         81 + 38 =6411

 6411                      6410 - 6411 

=> Milk : Water = 110 : 11 = 10 : 1

 

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

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13 956
Q:

In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture?

A) 1:1 B) 2:1
C) 3:1 D) 1:2
 
Answer & Explanation Answer: A) 1:1

Explanation:

Quantity of alohol in the mixture = 40 x 5/8 = 25 lit

Quantity of water = 40 - 25 = 15 lit

According to question,

Required ratio = 20 - 40 x 20100 x 5815 - 40 x 20100 x 38 + 40 x 20100 = 2015 - 3 + 8 = 1 : 1

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9 1406
Q:

In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

A) 85 B) 60
C) 55 D) 45
 
Answer & Explanation Answer: B) 60

Explanation:

Let M litres milk be added


=> 60 + M40 = 31


=> 60 + M = 120


=> M = 60 lit.

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8 642
Q:

A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 

A) 31.8% B) 31%
C) 33.33% D) 29.85%
 
Answer & Explanation Answer: C) 33.33%

Explanation:

Now, take percentage of milk and applying mixture rule

25          100

       50

50            25  = 2 : 1

 

Hence required answer =  1/3 or 33.33%

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15 884
Q:

The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture? 

A) 3:2 B) 4:3
C) 2:3 D) 3:4
 
Answer & Explanation Answer: A) 3:2

Explanation:

Concentration of glucose are in the ratio = 12:35:45

Quantity of glucose taken from A = 1 liter out of 2

Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit

Quantity of glucose taken from C = 0.8 lit

So, total quantity of glucose taken from A,B and C = 3.6 lit

So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit

Ratio of glucose to alcohol = 3.6/2.4 = 3:2

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10 1126