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Q:

From  a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The  initial amount of wine in the container was:

A) 75 liters B) 100 liters
C) 150 liters D) 120 liters

Answer:   D) 120 liters

Explanation:

\frac{wine(left)}{water(added)}=\frac{343}{169}

It means    \frac{wine(left)}{wine(initial\: amount)}=\frac{343}{512}       \left ( \because \: \: 343+169=512 \right )

Thus ,       343x=512x\left ( 1-\frac{15}{k} \right )^{3}

\Rightarrow \: \: \frac{343}{512}=\left ( \frac{7}{8} \right )^{3}=\left ( 1-\frac{15}{k} \right )^{3}

\Rightarrow\: \: \left ( 1-\frac{15}{k} \right )=\frac{7}{8}=\left ( 1-\frac{1}{8} \right )

\Rightarrow \: \: K=120

Thus the initial amount of wine was 120 liters.

Q:

A mixture of 70 litres of Fruit Juice and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 12 1/2% water   ?

A) 2 lit B) 4 lit
C) 1 lit D) 3 lit
 
Answer & Explanation Answer: A) 2 lit

Explanation:

Quantity of fruit juice in the mixture = 90/100 (70) = 63 litres.

After adding water, juice would form 87 1/2% of the mixture.

Hence, if quantity of mixture after adding x liters of water, (87 1/2) / 100 x = 63 => x = 72

Hence 72 - 70 = 2 litres of water must be added.

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2 61
Q:

A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture ?

A) 5 lit B) 10 lit
C) 15 lit D) 20 lit
 
Answer & Explanation Answer: B) 10 lit

Explanation:

Number of liters of water in 150 liters of the mixture = 20% of 150 = 20/100 x 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 x (150 + P)
120 + 4P = 150 + P => P = 10 liters.

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1 100
Q:

640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ?

A) 360 ml B) 320 ml
C) 310 ml D) 330 ml
 
Answer & Explanation Answer: B) 320 ml

Explanation:

Here total parts of milk and water in the solution is 6+2 = 8 parts
1part = 640/8 = 80
old mixture contains 6parts of milk and 2 parts of water(6:2).
To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same.
i.e, 4 x 80 = 320 ml.

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4 435
Q:

Equal quantities of three mixtures of milk and water are mixed in the ratio 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is ?

A) 193 : 122 B) 97 : 102
C) 115 : 201 D) 147 : 185
 
Answer & Explanation Answer: A) 193 : 122

Explanation:

Given the three mixtures ratio as (1:2),(2:3),(3:4)

(1+2),(2+3),(3+4)

Total content = 3,5,7

Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105

105/3 = 35 , 105/5 = 21 , 105/7 = 15

Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4)

(35,70), (42,63), (45,60)

So overall mixture ratio of milk and water is

35+42+45 : 70+63+60

122:193

But in the question asked the ratio of water to milk = 193 : 122

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3 351
Q:

In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

A) 80% B) 70%
C) 75% D) 62%
 
Answer & Explanation Answer: A) 80%

Explanation:

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and

weight of a mixture = 60 + 15 = 75 gm.

So % of water = 100 x 60/75 = 80%.

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