A) 4 | B) 5 |

C) 8 | D) None of these |

Explanation:

Wine Water

8L 32L

1 : 4

20 % 80% (original ratio)

30 % 70% (required ratio)

In ths case, the percentage of water being reduced when the mixture is being replaced with wine.

so the ratio of left quantity to the initial quantity is 7:8

Therefore ,

=> = K = 5 Lit

A) 71.02% | B) 76.92% |

C) 63.22% | D) 86.42% |

Explanation:

Let the milk he bought is 1000 ml

Let C.P of 1000 ml is Rs. 100

Here let he is mixing K ml of water

He is getting 30% profit

=> Now, the selling price is also Rs. 100 for 1000 ml

=> 100 : K%

= 100 : 30

10 : 3 is ratio of milk to water

=> Percentage of milk = 10 x 100/13 = 1000/13 = 76.92%

A) 8:3 | B) 6:7 |

C) 7:5 | D) 11:7 |

Explanation:

Milk in 1-litre mixture of A = 4/7 litre.

Milk in 1-litre mixture of B = 2/5 litre.

Milk in 1-litre mixture of C = 1/2 litre.

By rule of alligation we have required ratio X:Y

X : Y

4/7 2/5

\ /

(Mean ratio)

(1/2)

/ \

(1/2 – 2/5) : (4/7 – 1/2)

1/10 1/1 4

So Required ratio = X : Y = 1/10 : 1/14 = **7:5**

A) 60 lit | B) 55 lit |

C) 45 lit | D) 50 lit |

A) 24 lit | B) 16 lit |

C) 32 lit | D) 8 lit |

Explanation:

Given mixture = 48 lit

Milk in it = 48 x 5/8 = 30 lit

=> Water in it = 48 - 30 = 18 lit

Let 'L' lit of water is added to make the ratio as 3:5

=> 30/(18+L) = 3/5

=> 150 = 54 + 3L

=> L = 32 lit.

A) 88.01 lit | B) 87.48 lit |

C) 87.51 lit | D) 87.62 lit |

Explanation:

For these type of problems,

Quantity of Diesel remained =

Here p = 12 , q = 120

=>

=> 120 x 0.9 x 0.9 x 0.9

=> 120 x 0.729

= 87.48 lit.