# Number, Ranking and Time Sequence Test Questions

A) None | B) One |

C) Two | D) Three |

Explanation:

**Given Number:** 4 2 1 5 7 9 3 6 8

**Ascending order: **1 2 3 4 5 6 7 8 9

Hence the required pairs are 12, 49, 16

A) Four | B) Three |

C) Six | D) Five |

Explanation:

7 4 2

7 4 6

7 4 1

7 4 6

Only at these placees 4 is preceded by 7 but not followed by 3

A) 23 | B) 31 |

C) 27 | D) 28 |

Explanation:

Clearly, A’s new position is 15th from the left. But this is the same as B’s earlier position which is 9th from the right.

A) 45 | B) 47 |

C) 46 | D) 48 |

A) 31 | B) 18 |

C) 32 | D) 19 |

Explanation:

Number students behind the nitin in rank = (49 - 18) = 31

Nitin is 32nd from the last

A) None | B) one |

C) Two | D) Three |

Explanation:

Given Number : 7346285

Ascending Number : 2345678

Answer is Two. Those digits are 3,4

A) 41 | B) 40 |

C) 28 | D) 27 |

Explanation:

Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.

We may consider the two cases as under:

**Case I: $\stackrel{3}{\leftarrow}C\stackrel{8}{\leftrightarrow}B\stackrel{5}{\leftrightarrow}A\stackrel{21}{\to}$**

Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40

**Case II: $\stackrel{3}{\leftarrow}CA\stackrel{5}{\leftrightarrow}B$**

Number of persons between A and C

= (8 - 6) = 2

$\because [C\stackrel{8}{\leftrightarrow}BA\stackrel{21}{\to}B]$

Clearly number of persons in the queue = (3+1+2+1+21) = 28

Now, 28 < 40. So, 28 is the minimum number of persons in the queue.

A) 37 | B) 39 |

C) 27 | D) 38 |