# Races and Games Question & Answers

## Races and Games

Quantitative aptitude questions are asked in many competitive exams and placement exam. 'Races and Games' is a category in Quantitative Aptitude. Quantitative aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT), MAT, GMAT, IBPS Exam, CSAT, CLAT, Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams, Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

We have a large database of problems on "Races and Games" answered with explanation. These will help students who are preparing for all types of competitive examinations.

In a 1 km race, A beats B by 28 meters in 7sec. Find A's time over the course?

 A) 5min,4sec B) 4min,3sec C) 2min,3sec D) 3min,4sec

Explanation:

B covers 28 meters in 7sec. So, B's time over the course = $\inline \fn_cm \frac{7}{28}\times 1000$=250 sec.

Whereas A's time over the course = 250 -7 = 243 sec.

i.e A's time over the course is 4min , 3 sec.

Subject: Races and Games - Quantitative Aptitude - Arithmetic Ability

3

At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?

 A) 30 points B) 20 points C) 10 points D) 12 points

Explanation:

A : B = 60 : 45.

A : C = 60 : 40.

$\inline&space;\fn_jvn&space;{\color{Black}\therefore&space;\frac{B}{C}=\left&space;(&space;\frac{B}{A}&space;\times&space;\frac{A}{C}\right&space;)=\left&space;(&space;\frac{45}{60}\times&space;\frac{60}{40}&space;\right&space;)=\frac{45}{40}=\frac{90}{80}=90:80}$

B can give C 10 points in a game of 90.

Subject: Races and Games - Quantitative Aptitude - Arithmetic Ability

6

In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:

 A) 22.75 m B) 25 m C) 19.5 m D) 18.5 m

Explanation:

A : B = 200 : 169.

A : C = 200 : 182.

$\inline&space;\fn_jvn&space;{\color{Black}&space;\frac{C}{B}=\left&space;(&space;\frac{C}{A}\times&space;\frac{A}{B}&space;\right&space;)=\left&space;(&space;\frac{182}{200}\times&space;\frac{200}{169}&space;\right&space;)=182:169}$

When C covers 182 m, B covers 169 m.

When C covers 350 m, B covers $\inline&space;\fn_jvn&space;{\color{Black}\left&space;(&space;\frac{169}{182}\times&space;350&space;\right&space;)m}$ = 325 m

Therefore, C beats B by (350 - 325) m = 25 m.

Subject: Races and Games - Quantitative Aptitude - Arithmetic Ability

5

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:

 A) 5.4m B) 4.5m C) 5m D) 6m

Explanation:

A : B = 100 : 90.

A : C = 100 : 87.

$\inline&space;\fn_jvn&space;{\color{Black}\therefore&space;\frac{B}{C}=\left&space;(&space;\frac{B}{A}&space;\times&space;\frac{A}{C}\right&space;)=\left&space;(&space;\frac{90}{100}\times&space;\frac{100}{87}&space;\right&space;)=\frac{30}{29}}$

When B runs 30 m, C runs 29 m.

When B runs 180 m, C runs $\inline&space;\fn_jvn&space;{\color{Black}\left&space;(&space;\frac{29}{30}&space;\times&space;180\right&space;)m}$=174m

$\inline&space;\fn_jvn&space;{\color{Black}\therefore&space;}$ B beats C by (180 - 174) m = 6 m.

Subject: Races and Games - Quantitative Aptitude - Arithmetic Ability

1

In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:

 A) 20m B) 25m C) 22.5m D) 9m

Distance covered by B in 9 sec. = $\inline&space;\fn_jvn&space;{\color{Black}&space;\left&space;(&space;\frac{100}{45}\times&space;9&space;\right&space;)m}$ = 20m
$\fn_jvn&space;{\color{Black}&space;\therefore&space;}$ A beats B by 20 metres.