Arithmetical Reasoning Questions

Q:

Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

A) Rs. 4, Rs. 23 B) Rs. 13, Rs. 17
C) Rs. 15, Rs. 14 D) Rs. 17, Rs. 13
 
Answer & Explanation Answer: B) Rs. 13, Rs. 17

Explanation:

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

Report Error

View Answer Workspace Report Error Discuss

195 5735
Q:

A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes ?

A) 32 rolls B) 54 rolls
C) 108 rolls D) 120 rolls
 
Answer & Explanation Answer: D) 120 rolls

Explanation:

Number of cuts made to cut a roll into 10 pieces = 9.

Therefore, Required number of rolls = (45 x 24)/9 = 120.

Report Error

View Answer Workspace Report Error Discuss

112 3314
Q:

Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ?

A) 20 years B) 22 years
C) 25 years D) 27 years
 
Answer & Explanation Answer: C) 25 years

Explanation:

Let Varun's age today = x years.

Then, Varun's age after 1 year = (x + 1) years.

Therefore x + 1 = 2 (x - 12)  x + 1 = 2x - 24  x = 25.

Report Error

View Answer Workspace Report Error Discuss

105 2628
Q:

If you write down all the numbers from 1 to 100, then how many times do you write 3 ?

A) 11 B) 18
C) 20 D) 21
 
Answer & Explanation Answer: C) 20

Explanation:

Clearly, From 1 to 100, there are ten numbers with 3 as the unit's digit - 3, 13, 23, 33, 43, 53, 63, 73, 83, 93 and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.

 

So, required number = 10 + 10 = 20.

Report Error

View Answer Workspace Report Error Discuss

37 2353
Q:

In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?

A) 18 B) 36
C) 45 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, 

R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 {\color{Blue} \Rightarrow } 6R = 108 {\color{Blue} \Rightarrow } R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

Report Error

View Answer Workspace Report Error Discuss

43 2175