A) 55% | B) 65% |

C) 75% | D) 85% |

Explanation:

Let original radius = R.

New radius = =

Original area = and new area =

Decrease in area = = 75%

A) Rs. 4082.40 | B) Rs. 1024.21 |

C) Rs. 2810.6 | D) Rs. 3214 |

Explanation:

Length of the first carpet = (1.44)(6) = 8.64 cm

Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)

= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m

Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40

A) 13 m | B) 14 m |

C) 15 m | D) 16 m |

Explanation:

the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is

=> mts.

A) 115 | B) 117 |

C) 116 | D) 114 |

Explanation:

Length = 6 m 24 cm = 624 cm

Width = 4 m 32 cm = 432 cm

HCF of 624 and 432 = 48

Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.

A) 15 m | B) 4 m |

C) 6 m | D) 9 m |

A) Rs. 3600 | B) Rs. 3800 |

C) Rs. 3900 | D) Rs. 3700 |

Explanation:

Area = (l + b – d) d

= (80 + 60 – 10)10

=> 1300 sq.mts

=> 1300 x 3 = Rs.3900