A) 55% | B) 65% |

C) 75% | D) 85% |

Explanation:

Let original radius = R.

New radius = =

Original area = and new area =

Decrease in area = = 75%

A) 720 | B) 600 |

C) 660 | D) 6000 |

Explanation:

Let the number of bricks be 'N'

10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N

10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.

A) 108 sq.cm | B) 112 sq.cm |

C) 116 sq.cm | D) 120 sq.cm |

Explanation:

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle =1/2 x base x height => 1/2 x 24 x 10 = 120 sq.cm

A) Rs. 4082.40 | B) Rs. 1024.21 |

C) Rs. 2810.6 | D) Rs. 3214 |

Explanation:

Length of the first carpet = (1.44)(6) = 8.64 cm

Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)

= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m

Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40

A) 13 m | B) 14 m |

C) 15 m | D) 16 m |

Explanation:

the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is

=> mts.

A) 115 | B) 117 |

C) 116 | D) 114 |

Explanation:

Length = 6 m 24 cm = 624 cm

Width = 4 m 32 cm = 432 cm

HCF of 624 and 432 = 48

Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.