A) A | B) B |

C) C | D) D |

Explanation:

D _ C _ A --------(1)

D > B > C --------(2)

from (1) and (2)

D > B > C > A ---------(3)

Again E _ B _ A

But B > A, from (3)

So E > D > B > C > A [ Since B is the average of E and A so it is eqidistant from both E and A]

A) Rs. 175 | B) Rs. 220.75 |

C) Rs. 218.55 | D) Rs. 656.25 |

Explanation:

Assume Hebah has Rs. M

Since 25% more money at Poonam

=> Money at Poonam = M + (25% of M)

=> Money at Poonam = M + 0.25M = Rs. 1.25M

Money with Navaneet is thrice the money with Poonam,

=> Money at Navaneet = 3(1.25M) = Rs. 3.75M

Now, sum of all Money = (M + 1.25M + 3.75M) = Rs. 6M

But given the average of the money is Rs. 350

=> 6M/3 = 350

=> 2M = 350

=> M = 350/2 = Rs. 175

=> Amount of money Navaneet has = Rs. 3.75M = 3.75 x 175 = Rs. 656.25.

A) 56 | B) 64 |

C) 87 | D) 78 |

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

A) 33 yrs | B) 27 yrs |

C) 21 yrs | D) 29 yrs |

Explanation:

Let the avg age of 7 boys be 'p' years

Let the age of the girl be 'q' years

From given data,

The age of 7 boys = 7p years

Now the new average = (p + 1) when 22 yrs is replaced by q

Now the age of all 7 will become = 7(p + 1) yrs

Hence, 7p - 22 + q = 7(p + 1) yrs

7p - 22 + q = 7p + 7

q = 22 + 7 = 29

Therefore, the age of girl = q = 29 years.

A) 15 kg | B) 25 kg |

C) 35 kg | D) 45 kg |

Explanation:

Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.

Let k be the quantity of third variety of oil in the final mixture.

Let the ratio of initial quantity of oils be 'y'

From given details,

4x + 5 = 5y ..... (1)

5x + 10 = 7y .....(2)

8x + k = 9y ......(3)

By solving (1) & (2), we get

x = 5 & y = 5

From (3) => k = 5

Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.

A) 384 | B) 96 |

C) 192 | D) 206 |

Explanation:

Let the third subject marks be 'x'

=> Second subject marks = 2x

=> Third subject marks = 4x

Given avg = 224

x + 2x + 4x = 224 x 3

=> 7x = 224 x 3

=> x = 96

Hence, Second subject marks = 2x = 2 x 96 = 192.