A) A | B) B |

C) C | D) D |

Explanation:

D _ C _ A --------(1)

D > B > C --------(2)

from (1) and (2)

D > B > C > A ---------(3)

Again E _ B _ A

But B > A, from (3)

So E > D > B > C > A [ Since B is the average of E and A so it is eqidistant from both E and A]

A) 15 kg | B) 25 kg |

C) 35 kg | D) 45 kg |

Explanation:

Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.

Let k be the quantity of third variety of oil in the final mixture.

Let the ratio of initial quantity of oils be 'y'

From given details,

4x + 5 = 5y ..... (1)

5x + 10 = 7y .....(2)

8x + k = 9y ......(3)

By solving (1) & (2), we get

x = 5 & y = 5

From (3) => k = 5

Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.

A) 384 | B) 96 |

C) 192 | D) 206 |

Explanation:

Let the third subject marks be 'x'

=> Second subject marks = 2x

=> Third subject marks = 4x

Given avg = 224

x + 2x + 4x = 224 x 3

=> 7x = 224 x 3

=> x = 96

Hence, Second subject marks = 2x = 2 x 96 = 192.

A) 1000 (r - p) + pq | B) 1000 p + qr |

C) 1000 (r - q) + pr | D) 1000(p - q) + qr |

Explanation:

We need to find the total cost to send r messsages, r > 1000.

The first 1000 messsages will cost Rs.p each (Or)

The total cost of first 1000 messsages = Rs.1000p

The remaining (r - 1000) messsages will cost Rs.q each (Or)

The cost of the (r - 1000) = Rs.(r - 1000)y

Therefore, total cost = 1000p + rq - 1000q

= 1000(p - q) + qr

A) 134 | B) 137 |

C) 139 | D) 141 |

Explanation:

A) Rs. 4680 | B) Rs. 4420 |

C) Rs. 4960 | D) Rs. 5480 |

Explanation:

Let the expenditure on the 95 students be 'x'

Then,

95x + 500 = 120(x – 5)

95x + 500 = 120x - 600

120x - 95x = 1100

25x = 1100

=> x = 44

Therefore, total expenditure of the hostel becomes

95 x 44 + 500 = 4680.