A) 2(k+1) | B) 2k-3 |

C) 2k+1 | D) k+2 |

Explanation:

The 5 consecutive odd numbers whose average is k are (k-4), (k-2), k, (k+2), (k+4)

Again the average of (k-4), (k-2), k, (k+2), (k+4), (k+6), (k+8) is (k+2)

A) Rs. 4680 | B) Rs. 4420 |

C) Rs. 4960 | D) Rs. 5480 |

Explanation:

Let the expenditure on the 95 students be 'x'

Then,

95x + 500 = 120(x – 5)

95x + 500 = 120x - 600

120x - 95x = 1100

25x = 1100

=> x = 44

Therefore, total expenditure of the hostel becomes

95 x 44 + 500 = 4680.

A) 20 | B) 35 |

C) 54 | D) 40 |

Explanation:

Numbers of students in section A = x

∴ Numbers of students in section B and C = (100 – x)

∴ x 70 + (100 – x) 87.5 = 84 100

=> 70x + 87.5 100 – 87.5x = 8400

=> 8750 – 17.5x = 8400

=> 17.5x = 8750 – 8400 => x = 20.

A) Rs. 8840 | B) Rs. 11,500 |

C) Rs. 12,800 | D) Rs. 9450 |

Explanation:

Manager's monthly salary

= Rs. (1900 x 25 - 1500 x 24) = Rs. 11,500

A) 34 | B) 36 |

C) 38 | D) 40 |

Explanation:

M + Tu + W + Th = 4 x 48 = 192

Tu + W + Th + F = 4 x 46 = 184

M = 42

Tu + W + Th = 192 - 42 = 150

F = 184 – 150 = 34

A) 34 | B) 36 |

C) 35 | D) 37 |