A) 2(k+1) | B) 2k-3 |

C) 2k+1 | D) k+2 |

Explanation:

The 5 consecutive odd numbers whose average is k are (k-4), (k-2), k, (k+2), (k+4)

Again the average of (k-4), (k-2), k, (k+2), (k+4), (k+6), (k+8) is (k+2)

A) 40.36 | B) 41.24 |

C) 41.92 | D) 42.05 |

Explanation:

Given,

mean of 100 observations is 40

=> Total of 100 observations = 40 x 100 = 4000

84 is misread as 48

=> Difference = 84 - 48 = 36

=> Now, new total of 100 observations = 4000 + 36 = 4036

Correct Mean = 4036/100 = **40.36**

A) 97 | B) 98 |

C) 92 | D) 93 |

A) Rs. 175 | B) Rs. 220.75 |

C) Rs. 218.55 | D) Rs. 656.25 |

Explanation:

Assume Hebah has Rs. M

Since 25% more money at Poonam

=> Money at Poonam = M + (25% of M)

=> Money at Poonam = M + 0.25M = Rs. 1.25M

Money with Navaneet is thrice the money with Poonam,

=> Money at Navaneet = 3(1.25M) = Rs. 3.75M

Now, sum of all Money = (M + 1.25M + 3.75M) = Rs. 6M

But given the average of the money is Rs. 350

=> 6M/3 = 350

=> 2M = 350

=> M = 350/2 = Rs. 175

=> Amount of money Navaneet has = Rs. 3.75M = 3.75 x 175 = Rs. 656.25.

A) 56 | B) 64 |

C) 87 | D) 78 |

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

A) 33 yrs | B) 27 yrs |

C) 21 yrs | D) 29 yrs |

Explanation:

Let the avg age of 7 boys be 'p' years

Let the age of the girl be 'q' years

From given data,

The age of 7 boys = 7p years

Now the new average = (p + 1) when 22 yrs is replaced by q

Now the age of all 7 will become = 7(p + 1) yrs

Hence, 7p - 22 + q = 7(p + 1) yrs

7p - 22 + q = 7p + 7

q = 22 + 7 = 29

Therefore, the age of girl = q = 29 years.