1
Q:

138.009 + 341.981 - 146.305 = 123.6 + ?

A) 120.o85 B) 199.57
C) 295.05 D) None of these

Answer:   D) None of these

Explanation:

Let 138.009 + 341.981 - 146.305 = 123.6 + z

Then, z = (138.09+341.981) - (146.305+123.6)= 479.99 - 269.905 = 210.085

Q:

 (0.2 * 0.2+0.01)(0.1 * 0.1+ 0.02)^{-1}  is equal to

A) 5/3 B) 9/5
C) 41/4 D) 41/12
 
Answer & Explanation Answer: A) 5/3

Explanation:

Given expression = \inline \fn_jvn \frac{(0.2\times 0.2+ 0.01)}{(0.1\times 0.1 +0.02 )}=\frac{0.04+0.01}{0.01+0.02}=\frac{0.05}{0.03}=\frac{5}{3}

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3 596
Q:

When 52416 is divided by 312, the quotient is 168. what will be the quotient when 52.416 is divided by 0.0168?

A) 3.12 B) 312
C) 3120 D) None of these
 
Answer & Explanation Answer: C) 3120

Explanation:

Given , \inline \fn_jvn \frac{52416}{312}=168 \Leftrightarrow \frac{52416}{168}=312

Now,  \inline \fn_jvn \frac{52.416}{0.0168}=\frac{52416}{16.8}=\frac{52416}{168}\times \frac{1}{10}=(312\times 10)=3120

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5 588
Q:

54.327 x 357.2 x 0.0057 is same as

A) 5.4327 x 3.572 x5.7 B) 5.4327 x 3.572 x0.57
C) 54327 x 3572 x 0.0000057 D) None of these
 
Answer & Explanation Answer: A) 5.4327 x 3.572 x5.7

Explanation:

Number of decimal places in the given expression = 8

Number of decimal places in (A) = 8

Number of decimal places in (B) = 9 

Number of decimal places in (C)= 7

Clearly , the expresssion in (A) is the same as the given Expression.

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3 629
Q:

When 0.232323.... is converted into a fraction , then the result is 

 

A) 1/5 B) 2/9
C) 23/99 D) 23/100
 
Answer & Explanation Answer: C) 23/99

Explanation:

\inline \fn_jvn 0.232323...=0.\overline{23}=\frac{23}{99}

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7 1086
Q:

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases  by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity?

A) 2010 B) 2011
C) 2012 D) 2013
 
Answer & Explanation Answer: B) 2011

Explanation:

Suppose commodity X wil cost 40 paise more than Y after Z  years. Then,

       (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40

\inline \fn_jvn \Leftrightarrow  0.25Z = 0.40 + 2.10  \inline \fn_jvn \Leftrightarrow  Z= \inline \fn_jvn \frac{2.50}{0.25} =\frac{250}{25}=10

\inline \fn_jvn \therefore X will cost 40 paise more than Y 10  years after 2001 . i.e in 2011

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3 879