2
Q:

# Which of the following are in descending order of their value?

 A) 5/9, 7/11, 8/15, 11/17 B) 5/9, 8/15, 11/17, 7/11 C) 11/17 , 7/11, 8/15, 5/9 D) 11/17, 7/11, 5/9, 8/15

Answer:   D) 11/17, 7/11, 5/9, 8/15

Explanation:

Converting each of the given fractions into decimal form, we get

$\inline&space;\fn_jvn&space;\frac{5}{9}=0.55\:&space;,\frac{7}{11}=0.63\:&space;,\frac{8}{15}=0.533\:&space;,\frac{11}{17}=0.647$

Clearly, 0.647>0.63>0.55>0.533

so ,$\inline&space;\fn_jvn&space;\frac{11}{17}>\frac{7}{11}>\frac{5}{9}>\frac{8}{15}$

Q:

$(0.2 * 0.2+0.01)(0.1 * 0.1+0.02)^{-1}$ is equal to

 A) 5/3 B) 9/5 C) 41/4 D) 41/12

Answer & Explanation Answer: A) 5/3

Explanation:

Given expression = $\inline&space;\fn_jvn&space;\frac{(0.2\times&space;0.2+&space;0.01)}{(0.1\times&space;0.1&space;+0.02&space;)}=\frac{0.04+0.01}{0.01+0.02}=\frac{0.05}{0.03}=\frac{5}{3}$

Report Error

3 596
Q:

When 52416 is divided by 312, the quotient is 168. what will be the quotient when 52.416 is divided by 0.0168?

 A) 3.12 B) 312 C) 3120 D) None of these

Answer & Explanation Answer: C) 3120

Explanation:

Given , $\inline&space;\fn_jvn&space;\frac{52416}{312}=168&space;\Leftrightarrow&space;\frac{52416}{168}=312$

Now,  $\inline&space;\fn_jvn&space;\frac{52.416}{0.0168}=\frac{52416}{16.8}=\frac{52416}{168}\times&space;\frac{1}{10}=(312\times&space;10)=3120$

Report Error

5 588
Q:

54.327 x 357.2 x 0.0057 is same as

 A) 5.4327 x 3.572 x5.7 B) 5.4327 x 3.572 x0.57 C) 54327 x 3572 x 0.0000057 D) None of these

Answer & Explanation Answer: A) 5.4327 x 3.572 x5.7

Explanation:

Number of decimal places in the given expression = 8

Number of decimal places in (A) = 8

Number of decimal places in (B) = 9

Number of decimal places in (C)= 7

Clearly , the expresssion in (A) is the same as the given Expression.

Report Error

3 629
Q:

When 0.232323.... is converted into a fraction , then the result is

 A) 1/5 B) 2/9 C) 23/99 D) 23/100

Answer & Explanation Answer: C) 23/99

Explanation:

$\inline&space;\fn_jvn&space;0.232323...=0.\overline{23}=\frac{23}{99}$

Report Error

7 1086
Q:

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases  by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity?

 A) 2010 B) 2011 C) 2012 D) 2013

Answer & Explanation Answer: B) 2011

Explanation:

Suppose commodity X wil cost 40 paise more than Y after Z  years. Then,

(4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40

$\inline&space;\fn_jvn&space;\Leftrightarrow$  0.25Z = 0.40 + 2.10  $\inline&space;\fn_jvn&space;\Leftrightarrow$  Z= $\inline&space;\fn_jvn&space;\frac{2.50}{0.25}&space;=\frac{250}{25}=10$

$\inline&space;\fn_jvn&space;\therefore$ X will cost 40 paise more than Y 10  years after 2001 . i.e in 2011

Report Error

3 879