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Bank Exams Questions

A) (10 + 10/143 )min | B) (10 + 1/143 ) min |

C) (10 + 20/143 ) min | D) (10 + 30/143) min |

Explanation:

In a correct clock, the minute hand gains 55 min. spaces over the hour hand in 60 minutes.

To be together again, the minute hand must gain 60 minutes over the hour hand.

55 minutes are gained in 60 min.

60 min. are gained in [(60/55) * 60] min = min.

But they are together after 65 min.

Therefore, gain in 65 minutes = = min.

Gain in 24 hours = = 1440/143 min.

Therefore, the clock gains (10 + 10/143 )minutes in 24 hours.

A) 11pm | B) 12pm |

C) 1pm | D) 2pm |

Explanation:

Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.

Now 23 hrs 44 min. of this clock = 24 hours of correct clock.

356/15 hrs of this clock = 24 hours of correct clock

89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.

= 90 hrs of correct clock.

So, the correct time is 11 p.m.

A) Closed source software | B) Open source software |

C) Horizontal market software | D) vertical market software |

A) 7pm on wednesday | B) 20 min past 7pm on wednesday |

C) 15min past 7pm on wednesday | D) 8pm on wednesday |

Explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast. The watch gains min in a time of (7×24)+12 = 180 hours.

To show the correct time, it has to gain 5 min.

So the correct time will be shown on wednesday at 7:20 PM

A) 4360 | B) 4460 |

C) 4560 | D) 4660 |

Explanation:

Let the sum be Rs.P.then

P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)

On dividing,we get (1+R/100)^3=10025/6690=3/2.

Substituting this value in (i),we get:

P*(3/2)=6690 or P=(6690*2/3)=4460

Hence,the sum is rs.4460.