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Bank Exams Questions

A) 7pm on wednesday | B) 20 min past 7pm on wednesday |

C) 15min past 7pm on wednesday | D) 8pm on wednesday |

Explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast. The watch gains min in a time of (7×24)+12 = 180 hours.

To show the correct time, it has to gain 5 min.

So the correct time will be shown on wednesday at 7:20 PM

A) 2109 | B) 3109 |

C) 4109 | D) 6109 |

Explanation:

Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.

Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]

=Rs. [8000 * (23/20) * (23/20) * (21/20)]

= Rs. 11109. .

:. C.I. = Rs. (11109 - 8000) = Rs. 3109.

A) 17 | B) 19 |

C) 23 | D) 25 |

Explanation:

=16.85768.

Its characteristics is 16.

Hence, the number of digits in is 17.

A) 136 | B) 236 |

C) 336 | D) 436 |

Explanation:

let ABCD be the given parallelogram

area of parallelogram ABCD = 2 x (area of triangle ABC)

now a = 30m, b = 14m and c = 40m

Area of triangle ABC =

= = 168sq m

area of parallelogram ABCD = 2 x 168 = 336 sq m

A) 24min | B) 12min |

C) 13min | D) 14min |

Explanation:

In this type of problems the formuae is

(5*x+ or - t)*12/11

Here x is replaced by the first interval of given time. Here x is 5.

t is spaces apart

Case 1 : (5*x + t) * 12/11

(5*5 + 3) * 12/11

28 * 12/11 = 336/11= min

therefore the hands will be 3 min apart at 31 5/11 min past 5.

Case 2 : (5*x - t) * 12/11

(5*5 -3 ) * 12/11

22 *12/11 = 24 min

therefore the hands will be 3 min apart at 24 min past 5