# Bank Exams Questions

Q:

The diagonal of a rectangle is $\inline \sqrt{41}$ cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

 A) 18 B) 28 C) 38 D) 48

Explanation:

$\inline \sqrt{l^{2}+b^{2}}=\sqrt{41}$ (or)   ${\color{Black}&space;l^{2}+b^{2}=41}$

Also, $\inline lb=20$

${\color{Black}&space;(l+b)^{2}=l^{2}+b^{2}+2lb}$

= 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

103 6689
Q:

What is the rate of interest p.c.p.a.?

I. An amount doubles itself in 5 years on simple interest.

II. Difference between the compound interest and the simple interest earned on a certain amount in 2 years is Rs. 400.

III. Simple interest earned per annum is Rs. 2000

 A) I only B) II and III only C) All I, II and III D) I only or II and III only

Answer & Explanation Answer: D) I only or II and III only

Explanation:

$\inline \fn_jvn I. \frac{P\times R\times 5}{100}=P\Rightarrow R=20$

$\inline \fn_jvn II.P\left ( 1+\frac{R}{100} \right )^2-P-\frac{P\times R\times 2}{100}=400\Rightarrow pR^{2}=4000000$

$\inline \fn_jvn III.\frac{P\times R\times 1}{100}=2000\Rightarrow PR=200000$

$\inline \fn_jvn \therefore \frac{PR^{2}}{PR}=\frac{4000000}{200000}\Rightarrow R=20$

Thus I only or (II and III) give answer.

$\inline \fn_jvn \therefore$ Correct answer is (D)

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Q:

One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?

 A) 110 B) 120 C) 130 D) 140

Explanation:

Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8 =120 sq. m

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Q:

Find the ratio of the areas of the incircle and circumcircle of a square.

 A) 1:1 B) 1:2 C) 1:3 D) 1:4

Explanation:

Let the side of the square be x. Then, its diagonal = ${\color{Black}\sqrt{2x^{2}}=\sqrt{2}x}$

Radius of incircle = $\inline \fn_cm \frac{x}{2}$

Radius of circum circle= ${\color{Black}\sqrt{{2}}\times&space;\frac{x}{2}=\frac{x}{\sqrt{2}}}$

Required ratio = $\inline \fn_cm \frac{\prod x^{2}}{4}:\frac{\prod x^{2}}{2}=\frac{1}{4}:\frac{1}{2}=1:2$

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Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

 A) 110 B) 120 C) 130 D) 140

Explanation:

let length = x and breadth = y then

2(x+y) = 46  $\inline \fn_cm \Rightarrow$  x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

$\inline \fn_cm \Rightarrow$x²+y²+2xy= 529

289+ 2xy = 529

$\inline \fn_cm \Rightarrow$ xy = 120

area = xy = 120 sq.cm