GRE Questions

---

Dr. G. D. Bist, Guinness Record Holder, the first-ever Ph.D. in Stenography in the world.

He had achieved a highest speed of 250 w.p.m. in Shorthand.

Let each instalment be Rs.x .

1st year =  [x + (x * 12 * 2)/100] 

2nd year = [ x + (x *12 * 1)/100] 

3rd year = x 

Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092 

3x + ( 24x/100 ) + ( 12x/100 )  = 1092 

336x =109200

Therefore, x = 325 

Each instalment = Rs. 325

Let the time be 'n' years, Then

$800\times {\left(1+\frac{5}{100}\right)}^{2}n=926.10 <=> {\left(1+\frac{5}{100}\right)}^{2}n=\frac{9261}{8000}<=>{\left(\frac{21}{20}\right)}^{2}n={\left(\frac{21}{10}\right)}^3$

n = 3/2 or n= 1$\frac{1}{2}$ Years 

Let sum = X. Then S.I = 16x/25

Let rate = R% and Time = R years.

Therefore,  (x * R * R)/100 = 16x/25   =>  R = 40/5 = 8

Therefore, Rate = 8% and Time = 8 years.