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GRE Questions

A) Dr. G. D. Bist | B) J.R.D. Tata |

C) J.M. Tagore | D) Khudada Khan |

Explanation:

**Dr. G. D. Bist**, Guinness Record Holder, the first-ever Ph.D. in Stenography in the world.

He had achieved a highest speed of **250 w.p.m**. in Shorthand.

A) 12.5% | B) 13.5% |

C) 11.5% | D) 14.5% |

Explanation:

Let principal = P, Then, S.I.= P and Time = 8 years

We know that S.I. = PTR/100

**Rate** = [(100 x P)/ (P x 8)]% = 12.5% per annum.

A) Rs.325 | B) Rs.545 |

C) Rs.560 | D) Rs.550 |

Explanation:

Let each instalment be Rs.x .

1st year = [x + (x * 12 * 2)/100]

2nd year = [ x + (x *12 * 1)/100]

3rd year = x

Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092

3x + ( 24x/100 ) + ( 12x/100 ) = 1092

336x =109200

Therefore, x = 325

Each instalment = Rs. 325

A) 1.5 | B) 2.5 |

C) 3.5 | D) 4.5 |

Explanation:

Let the time be 'n' years, Then

$800\times {\left(1+\frac{5}{100}\right)}^{2}n=926.10={\left(1+\frac{5}{100}\right)}^{2}n=\frac{9261}{8000}={\left(\frac{21}{20}\right)}^{2}n={\left(\frac{21}{10}\right)}^{3}$

n = 3/2 or n= 1$\frac{1}{2}$ Years

A) 650 | B) 690 |

C) 698 | D) 700 |

Explanation:

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 - 117) = Rs. 698

A) 2 years | B) 2.5 years |

C) 3 years | D) 4 years |

Explanation:

Amount = Rs.(30000+4347) = Rs.34347

let the time be n years

Then,30000(1+7/100)^n = 34347

(107/100)^n = 34347/30000 = 11449/10000 = (107/100)^2

n = 2years

A) 10 : 5 | B) 15 : 2 |

C) 20 : 2 | D) 25 : 2 |

Explanation:

Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number.

US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.

Now US : Indian = 25 : 10, and Indian : British = 10 : 2

Hence the two ratios can be combined and US : British = 25 : 2

A) 800, 14% | B) 800, 13% |

C) 800, 12% | D) 800, 19% |

Explanation:

S.I. for 1 ½ years = Rs (1164 - 1008) = Rs 156 .

S.I. for 2 years = Rs (156 x $\frac{2}{3}$ x 2)= Rs 208.

Therefore, Principal = Rs (1008 - 208) = Rs 800.

Now, P = 800, T= 2 and S.I. = 208.

Therefore, Rate = (100 x S.I.) / (P x T) = [ (100 x 208)/(800 x 2)]% = 13%