A) 77 | B) 88 |

C) 99 | D) 110 |

Explanation:

Product of numbers = 11 x 385 = 4235

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 ab = 35

Now, co-primes with product 35 are (1,35) and (5,7)

So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)

Since one number lies 75 and 125, the suitable pair is (55,77)

Hence , required number = 77

A) 6 | B) 8 |

C) 4 | D) 9 |

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

A) 64 | B) 69 |

C) 71 | D) 58 |

Explanation:

To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51).

Therefore, HCF of 923, 1207 and 1349 is 71.

A) 487 | B) 585 |

C) 635 | D) 705 |

Explanation:

The smallest possible number of books = L.C.M of 5, 9 and 13.

Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.

A) 32 | B) 48 |

C) 60 | D) 152 |

A) 26 | B) 24 |

C) 18 | D) 12 |

Explanation:

Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600

Find a number which exactly divide all these numbers

That is HCF of 18000, 9600& 3600

All the value has 00 at end so the factor will also have 00.

HCF for 180, 96 & 36.

Factors of

180 = 3 x 3 x 5 x 2 x 2

96 = 2 x 2 x 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

Common factors are 2x2×3=12

Actual HCF is 1200

Gold Coins will be in 15 rooms

Silver Coins will be in 8 rooms

Bronze Coins will be in 3 rooms

Total rooms will be (15+8+3) = 26 rooms.