A) 77 | B) 88 |

C) 99 | D) 110 |

Explanation:

Product of numbers = 11 x 385 = 4235

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 ab = 35

Now, co-primes with product 35 are (1,35) and (5,7)

So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)

Since one number lies 75 and 125, the suitable pair is (55,77)

Hence , required number = 77

A) 47 | B) 46 |

C) 37 | D) 35 |

Explanation:

The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.

Number of cans of Maaza = 368/16 = 23

Number of cans of Pepsi = 80/16 = 5

Number of cans of Sprite = 144/16 = 9

The total number of cans required = 23 + 5 + 9 = 37 cans.

A) 360 | B) 180 |

C) 90 | D) 120 |

Explanation:

4 x 27 x 3125 = ;

8 x 9 x 25 x 7 =

16 x 81 x 5 x 11 x 49 =

H.C.F = = 180.

A) 63 and 49 | B) 64 and 48 |

C) 62 and 46 | D) 64 and 49 |

Explanation:

Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y

Difference = 14

=> 7x - 7y = 14

=> x - y = 2

product of numbers = product of their hcf and lcm

=> 7x * 7y = 441 * 7

=> x * y = 63

Now, we have

x * y = 63 , x - y = 2

=> x = 9 , y = 7

The numbers are 7x and 7y

=> 63 and 49

A) 13/125 | B) 14/57 |

C) 11/120 | D) 16/41 |

Explanation:

Let the numbers be a and b.

We know that product of two numbers = Product of their HCF and LCM

Then, a + b = 55 and ab = 5 x 120 = 600.

=> The required sum = (1/a) + (1/b) = (a+b)/ab

=55/600 = 11/120

A) 7 lts | B) 14 lts |

C) 98 lts | D) 42 lts |

Explanation:

To know the the measuring cylinder that can fill all the given capacities , they must be divisible by the required number.

98,182,266 all are divisible by 14

So 14 litres is the largest cylinder that can fill all the given cylinders.

(or)

The other method is take HCF of all given capacities i.e 98, 182 and 266.