A) 40 | B) 80 |

C) 120 | D) 200 |

Explanation:

Let the numbers be 3x, 4x and 5x.

Then, their L.C.M. = 60*x*.

So, 60*x* = 2400 or x = 40.

The numbers are (3 x 40), (4 x 40) and (5 x 40).

Hence, required H.C.F. = 40.

A) 63 | B) 31 |

C) 16 | D) 27 |

Explanation:

To get the least number of coconuts :

LCM = 30 => 30 + 1 = 31

A) 47 | B) 46 |

C) 37 | D) 35 |

Explanation:

The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.

Number of cans of Maaza = 368/16 = 23

Number of cans of Pepsi = 80/16 = 5

Number of cans of Sprite = 144/16 = 9

The total number of cans required = 23 + 5 + 9 = 37 cans.

A) 360 | B) 180 |

C) 90 | D) 120 |

Explanation:

4 x 27 x 3125 = ;

8 x 9 x 25 x 7 =

16 x 81 x 5 x 11 x 49 =

H.C.F = = 180.

A) 63 and 49 | B) 64 and 48 |

C) 62 and 46 | D) 64 and 49 |

Explanation:

Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y

Difference = 14

=> 7x - 7y = 14

=> x - y = 2

product of numbers = product of their hcf and lcm

=> 7x * 7y = 441 * 7

=> x * y = 63

Now, we have

x * y = 63 , x - y = 2

=> x = 9 , y = 7

The numbers are 7x and 7y

=> 63 and 49

A) 13/125 | B) 14/57 |

C) 11/120 | D) 16/41 |

Explanation:

Let the numbers be a and b.

We know that product of two numbers = Product of their HCF and LCM

Then, a + b = 55 and ab = 5 x 120 = 600.

=> The required sum = (1/a) + (1/b) = (a+b)/ab

=55/600 = 11/120