Do the math and you will see that this puzzle is based on the fact taht (2)=1 and 1+1=2

From the assumption and trial and error method,

last three digits sum must leave the same digit as the answer. It is possible only if the answer must be units digit number leaving tens digit as carry.

And the possible 3rd digit is 5. Since 5 + 5 + 5 = 15

Now, 2nd step is 1 + x + x + x = 5

=> 3x = 4

It is possible with x = 8. 8 + 8 + 8 + 1 = 25 leaving 2 as carry.

Now, 3rd step is 2 + x + x + x = 5 => x = 1

Hence, the three dgits are 1, 8, 5.

**185 + 185 + 185 = 555. **

A) 4 | B) 8 |

C) 12 | D) 16 |

Explanation:

Here given that 9 = 63, 8 = 48, 7=35, ...

The given question follows a pattern that

**9 x (9 - 2) = 9 x 7 = 63**

**8 x (8 - 2) = 8 x 6 = 48**

**7 x (7 - 2) = 7 x 5 = 35**

Similarly, **4 x (4 - 2) = 4 x 2 = 8.**

A) 44 | B) 45 |

C) 46 | D) 50 |

Explanation:

Number of squares in the given figure is

**16 + 9 + 19 + 1 = 45.**

A) 79 hrs | B) 72 hrs |

C) 52 hrs | D) 18 hrs |

Explanation:

From the given data,

18 snakes can eat 18 bananas in 18 hrs.

=> 1 snake can eat 1 banana in 18 hrs

=> 79 snakes can eat 79 bananas in 18 hrs.

Hence, **18 hrs.**

Let the required number be 'X'

**Condition 1** :

$\frac{X}{X}=2X\phantom{\rule{0ex}{0ex}}=2{X}^{2}=X\phantom{\rule{0ex}{0ex}}=\mathbf{}\mathit{X}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{1}}{\mathbf{2}}$

**Condition 2 :**

**$\mathrm{X}\times \mathrm{X}=\frac{\mathrm{X}}{2}\phantom{\rule{0ex}{0ex}}=\mathbf{X}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{1}}{\mathbf{2}}$**

**Therefore, **$\left(\frac{\mathbf{1}}{\mathbf{2}}\right)$ is the number which becomes double when it is divided by itself and becomes half when it is multiplied by itself.

A) 4! | B) 5! |

C) 6! | D) Can't be determined |

Explanation:

NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions.

And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions.

Therefore, Can't be determined.

A) 1/8 | B) 0 |

C) 1/4 | D) 1 |

Explanation:

Non collision can happen only when all the cars move in same direction.

That is either all cars moving in clockwise direction or all cars moving in anti clockwise direction.

P(all cars not colliding)

= P(all cars moving in the same direction)

= P(all cars moving in clockwise direction) + P(all cars moving in anticlockwise direction)

= [p(A --> C) x p(C --> B) x p(B --> A)] + [p(A --> B) x p(B --> C) x p(C --> A)]

= [1/2 x 1/2 x 1/2] + [1/2 x 1/2 x 1/2]

= 1/8 + 1/8

= 1/4