13
Q:

# In a cricket match, five batsmen P, Q, R, S and T scored an average of 36 runs. S Scored 5 more than T; T scored 8 fewer than P; Q scored as many as S and T combined; and Q and R scored 107 between them. How many runs did T score ?

 A) 20 B) 29 C) 28 D) 24

Answer:   A) 20

Explanation:

Let the runs scored by P, Q, R, S and T be  a, b, c, d and e

From given data,

a + b + c + d + e = 36 x 5 = 180
b + c = 107
Let a = x
e = x-8
d = x-3
now 3x - 11 + 107 = 180
3x = 84
x = 28
e's score = 28-8 = 20

Q:

5x - 6 = 3x - 8

Solve the above equation.

 A) 2 B) -1 C) -2 D) 1

Answer & Explanation Answer: B) -1

Explanation:

Given 5x - 6 = 3x - 8

5x - 3x = -8 + 6

2x = -2

=> x = -1.

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0 93
Q:

3 x 3 + 3 - 3 + 3 = ?

 A) 9 B) 12 C) -3 D) 3

Answer & Explanation Answer: B) 12

Explanation:

Using BODMAS law,

3 x 3 + 3 - 3 + 3 =

3 x 3 = 12

= 12 + 3 - 3 + 3

=  9 + 3

= 12

Hence, 3 x 3 + 3 - 3 + 3 = 12.

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1 128
Q:

What is x squared plus x squared?

 A) 4x B) 2x^2 C) x^4 D) 2x

Answer & Explanation Answer: B) 2x^2

Explanation:

In an algebraic expression, like terms are terms that contain the same variables raised to the same powers. Calculating x-squared plus x-squared is a matter of combining like terms.

Now x^2 + x^2 = 2x^2

Hence, x-squared plus x-squared is equal to 2 times x squared.

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1 121
Q:

What is

 A) 0 B) 42 C) 50 D) 57

Answer & Explanation Answer: C) 50

Explanation:

Given 7 + 7/7 + 7 x 7 - 7

By using BODMAS rule,

7 + 1 + 7 x 7 - 7

= 8 + 49 - 7

= 57 - 7

= 50.

Hence 7 + 7/7 + 7 x 7 - 7 = 50.

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1 394
Q:

Find the Value of ?

 A) 81 B) 77 C) 73 D) 89

Answer & Explanation Answer: D) 89

Explanation:

This can be done in a method called Approximation.

Now,

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6 377
Q:

Can you Solve  =

 A) 112 B) 56 C) 0 D) 98

Answer & Explanation Answer: A) 112

Explanation:

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8 350
Q:

The last two digits of ${\mathbf{2151}}^{\mathbf{415}}$?

 A) 81 B) 61 C) 91 D) 51

Answer & Explanation Answer: D) 51

Explanation:

Unit digit of this expression is always 1 as the base ends with 1.

For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.

i.e, tenth place digit in 2151 is 5 and

tenth place digit in power 415 is 1

And the units digit in the product of 5 x 1 = 5

Therefore, last two digits of ${\mathbf{2151}}^{\mathbf{415}}$ is 51.

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7 576
Q:

What is the value of P in the following Equation ?

 A) 3.9 B) 4.1 C) 3.7 D) 4.5

Answer & Explanation Answer: D) 4.5

Explanation:

Given equation is

Here it is in the form of

Here m = 2.5 , n = p, m+n = 7

=> 2.5 + p = 7

=> p = 7 - 2.5

=> p = 4.5

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9 741