A) 41 | B) 40 |

C) 28 | D) 27 |

Explanation:

Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.

We may consider the two cases as under:

**Case I: **

Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40

**Case II: **

Number of persons between A and C

= (8 - 6) = 2

Clearly number of persons in the queue = (3+1+2+1+21) = 28

Now, 28 < 40. So, 28 is the minimum number of persons in the queue.

A) 33 | B) 36 |

C) 35 | D) 34 |

Explanation:

Total number of students in the class = **28 + 6** i.e, from top(7-1)

28 + 6 = 34

A) 1 | B) 2 |

C) 3 | D) 0 |

Explanation:

Only one such symbol is there in the given arrangement.

It is **4@5.**

A) 11 | B) 19 |

C) 13 | D) 17 |

Explanation:

Here total number of boys in the row = 11 + 19 = 13 + 17 = 30

Here after exchanging the places of Haran & Manoj

=> Manoj replaces Harans place of 11th from left

But in the question he asked Manoj's place from right = 30 - 11 = 19th place.

A) 25th and 21st | B) 26th and 22nd |

C) 20th and 24th | D) 24th and 20th |

Explanation:

Number of students behind Manoj in rank = (31 - 7) = 24.

So, Manoj is 25th from the bottom.

Number of students behind Satya in rank = (31 - 11) = 20.

So, Satya is 21st from the bottom.

A) 8 | B) 9 |

C) 2 | D) 4 |

Explanation:

According to the question, after the position of the first and third digit interchanged new numbers are

789, 415, 856, 784, 404, 962

962, 856, 789, 784, 404, 415

Here the second lowest number is 404 and the last digit of it is '4'.