A) 32 | B) 24 |

C) 26 | D) 38 |

Explanation:

Let the first number be K and second number be L

Then, 2K + 3L = 100.....(1)

3K + 2L = 120.......(2)

solving (1)&(2), we get

K = 32 and L = 12

Hence the largest number is 32.

A) 146 | B) 203 |

C) 345 | D) 96 |

Explanation:

From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ?

Now arranging the given numbers in descending order.

837 746 519 495 328

519 - 746/2 = 519 - 373 = 146.

A) 404 | B) 585 |

C) 415 | D) 602 |

Explanation:

Given numbers are 585 546 514 404 206 369

Then interchanging the 1st and 3rd digits of the given numbers, we get

585 645 415 404 602 963

Now, arranging them in ascending order

963 645 602 585 415 404

Then the last second number is 415.

A) 42 & 24 | B) 38 & 26 |

C) 36 & 24 | D) 44 & 28 |

Explanation:

Let

x = peacocks

y = deers

2x + 4y = 200

x + y = 72

y = 72 - x

2x + 288 - 4x = 200

x = 44 peacocks

y = 28 deers

A) 4 | B) 6 |

C) 3 | D) 1 |

Explanation:

Number = quotient x divisor + remainder;

so, here

number = 138 k + 26

=> (23 x 6k) + (23+3)

=> 23(6k+1)+3

so, remainder is 3.