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# The sum of first 45 natural numbers is:

Answer:
• Related Questions

What smallest number of 6 digit is divisible by 111?

Answer

Smallest number of 6 digits is 100000

on dividing 100000 by 111 we get 100 as remainder

$\inline&space;\fn_jvn&space;\therefore$ Number to be added = (111 -100) = 11

$\inline&space;\fn_jvn&space;\therefore$ Required Number  = 100011

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

19

The value of

$\inline \fn_jvn \left [ \frac{2^{n}+2^{n-1}}{2^{n+1}-2^{n}} \right ]$ is:

Answer

$\inline \fn_jvn \frac{2^{n}+2^{n-1}}{2^{n+1}-2^{n}} =\frac{2^{n-1}(2+1)}{2^{n}(2-1)}=\frac{\frac{3\times 2^{n}}{2}}{2^{n}}=\frac{3}{2}$

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

19

The difference of two numbers is 11 and (1/5)th of their sum is 9. The numbers are

Answer

Let the numbers be x and (x-11)

$\inline \fn_jvn \frac{1}{5}\times (x+x-11)=9$

$\inline&space;\fn_jvn&space;\Rightarrow$   x = 28

$\inline&space;\fn_jvn&space;\therefore$ Another Number is (28 - 11) = 17

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

4

A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?

Answer

Number = ( 779 x a) + 47, where "a" is the quotient

= (19 x 41 x a) + (19 x 2) + 9

= 19 x (41a + 2) + 9

= 19 x (New quotient) + 9

$\inline&space;\fn_jvn&space;\therefore$  Required remainder = 9

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

4

(51 + 52 + 53 + .........+100) is equal to

Answer

51 + 52 + 53 + ...........+ 100

= (1 + 2 + 3 + .... + 100) - (! + 2 + 3 + ...... + 50)

=$\inline \fn_jvn \left ( \frac{100\times 101}{2}-\frac{50\times 51}{2} \right )$

=  (5050 - 1275) = 3775

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Subject: Numbers - Quantitative Aptitude - Arithmetic Ability

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