A) 60 | B) 52 |

C) 45 | D) 35 |

Explanation:

Let the total applicants be 100

Then, 20% got 85 marks

i.e 20 85 = 1700

and 25% got 95 marks

i.e 25 95 = 2375

Now, the remaining applicants are 55 and let the average marks scored by them be x.

2375 + 1700 + 55 x = 60 100

6000 - 4075 = 55x

55x=1925

x=

x=35.

A) Rs.1,92,000 | B) Rs.2,24,000 |

C) Rs.1,26,000 | D) Rs.3,42,000 |

Explanation:

One-quarter of one-seventh = 1/4 x 1/7

= 1/28

Now, 1/28 of a land costs = Rs. 30,000

Thus, 8/35 of the land will cost = 30,000 x 28 x 4/15

= Rs. 2,24,000.

A) 31/25 | B) 15/17 |

C) 14/25 | D) 11/16 |

A) 49.6% | B) 50.4% |

C) 33.67% | D) 66.66% |

Explanation:

As these three strategies P, Q and R are independent so these will cut cost one after the other.

If initial cost is Rs 100, then

20% cost is cut after initializing strategy P, then cost will remain 80% = 80

further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56

further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4

Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.

A) Thursday | B) Friday |

C) Tuesday | D) Monday |

Explanation:

Given monday population = 3000

Per day 20% increase in population.

Tuesday population = 3000 + 3000x20/100 = 3000 + 600 = 3600

Wednesday population =3600 + 3600x20/100 = 3600 + 720 = 4320

Thursday population = 4320 + 4320x20/100 = 4320 + 864 = 5184

So that day is Thursday.

A) 160 | B) 120 |

C) 140 | D) 180 |

Explanation:

Given total number of cows = k

Now, 1st son share = k/2

2nd son share = k/4

3rd son share = k/5

4th son share = 9

(k) + (k/4) + (k/5) + 9 = k

=> k - (19k/20) = 9

=> (20k-19k)/20 = 9

=> k = 180.