7
Q:

# In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ?

 A) 60 B) 52 C) 45 D) 35

Explanation:

Let the total applicants be 100
Then, 20% got 85 marks

i.e 20 $\fn_jvn \small \times$ 85 = 1700

and 25% got 95 marks

i.e 25 $\fn_jvn \small \times$ 95 = 2375

Now, the remaining applicants are 55 and let the average marks scored by them be x.

$\therefore$ 2375 + 1700 + 55$\fn_jvn \small \times$ x  =  60 $\fn_jvn \small \times$ 100

$\Rightarrow$ 6000 - 4075 = 55x
$\Rightarrow$ 55x=1925
$\Rightarrow$ x= $\inline \frac{1925}{55}$
$\Rightarrow$x=35.

Q:

45% of 750  -  25% of 480 = ?

 A) 337.50 B) 217.50 C) 376.21 D) 120

Explanation:

Given expression = ($\inline \fn_jvn \small \frac{45}{100}$  x 750) - ($\inline \fn_jvn \small \frac{25}{100}$  x 480) = (337.50 - 120) = 217.50

1 4
Q:

What percent is 120 of 85 ?

 A) 133.33 % B) 141.17 % C) 145.54 % D) 139.29 %

Explanation:

$\fn_jvn \small \frac{Px85}{100}=120$

=> p = 12000/85 = 141.17 %

1 31
Q:

A number increased by 30% gives 390. The number is

 A) 180 B) 300 C) 480 D) 260

Explanation:

Let the number be 'N'
Given N + 30N/100 = 390
=> 130N/100 = 390
=> N = 390 x 10/13
=> N = 300.

1 32
Q:

If 25% of a number is subtracted from a second number, the second number reduces to its four-sixth. What is the ratio of the first number to the second number  ?

 A) 4:3 B) 2:3 C) 3:2 D) 5:3

Explanation:

Let the numbers be p & q

q-p/4 = 4q/6

=> q-4q/6 = p/4

=> 2q/6 = p/4

=> p/q = 4/3

2 56
Q:

A number, when 35 is subtracted from it, reduces to its 80 percent. What is four - fifth of that number  ?

 A) 175 B) 140 C) 135 D) 95