A) 2048 | B) 1296 |

C) 4096 | D) 576 |

Explanation:

Every ball can be distributed in 4 ways.

Hence the required number of ways = 4 x 4 x 4 x 4 x 4 x 4 = 4096

A) 186 | B) 144 |

C) 136 | D) 120 |

Explanation:

In given word OLIVER there are 3 vowels E, I & O. These can be arranged in only one way as dictionary order E, I & O.

There are 6 letters in thegiven word.

First arrange 3 vowels.

This can be done in 6C3 ways and that too in only one way.(dictionary order E, I & O)

Remaining 3 letters can be placed in 3 places = 3! ways

Total number of possible ways of arranging letters of OLIVER = 3! x 6C3 ways

= 6x5x4 = 120 ways.

A) 120 | B) 256 |

C) 192 | D) 244 |

Explanation:

We are having with digits 2, 3, 4, 5 & 6 and numbers greater than 4000 are to be formed, no digit is repeated.

The number can be 4 digited but greater than 4000 or 5 digited.

Number of 4 digited numbers greater than 4000 are

4 or 5 or 6 can occupy thousand place => 3 x 4P3 = 3 x 24 = 72.

5 digited numbers = 5P5 = 5! = 120

So the total numbers greater than 4000 = 72 + 120 = 192

A) 5! | B) 6! |

C) 4! | D) Can't determine |

Explanation:

NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions.

And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions.

Therefore, Can't be determined.

A) 5 | B) 6 |

C) 7 | D) 8 |

Explanation:

The following arrangements satisfy all 3 conditions.

Arrangement 1: 3 books in a row; 12 rows.

Arrangement 2: 4 books in a row; 9 rows.

Arrangement 3: 6 books in a row; 6 rows.

Arrangement 4: 9 books in a row; 4 rows.

Arrangement 5: 12 books in a row; 3 rows.

Therefore, the possible arrangements are 5.

A) 11!/2 | B) 1024 |

C) 11! | D) 2048 |

Explanation:

Given 11 questions of type True or False

Then, Each of these questions can be answered in 2 ways (True or false)

Therefore, no. of ways of answering 11 questions = = 2048 ways.