|A) 5/204||B) 1/204|
|C) 13/204||D) None of these|
Let A, B, C be the events of getting a white ball in first, second and third draw respectively, then
Required probability =
Now, P(A) = Probability of drawing a white ball in first draw = 4/18 = 2/9
When a white ball is drawn in the first draw there are 17 balls left in the urn, out of which 3 are white
Since the ball drawn is not replaced, therefore after drawing a white ball in the second draw there are 16 balls left in the urn, out of which 2 are white.
Hence the required probability =