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# The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

 A) 15 B) 16 C) 18 D) 25

Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

${\color{Black}&space;\therefore&space;\left&space;(&space;\frac{20-x}{x}\times&space;100=25&space;\right&space;)}$

$\inline \fn_jvn \Rightarrow$2000 - 100x = 25x

$\inline \fn_jvn \Rightarrow$125x=2000

$\inline \fn_jvn \Rightarrow$x=16

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• Related Questions

A women goes to market with Rs.500 to buy oranges.the prices of the oranges have decreased by 10% so he could buy 2kg more with the amount she had.What was the original price of the oranges ?

 A) 22.77 B) 25.77 C) 27.77 D) 29.77

Explanation:

If the price of the oranges decreases by 10%, the woman would save 10% of the money that is Rs.50 to buy the same amount as before.Now in Rs50 she can buy 2 kg more, therefore the current price of 1 kg of oranges is Rs25.Now this current price is after 10% reduction.

Therefore, the original price = $\inline \frac{25}{0.9}=Rs\, 27.77$

Subject: Profit and Loss - Quantitative Aptitude - Arithmetic Ability

15

A retailer buys product from a shopkeeper at discount of 40% on the list price (marked price) and sells them to the customer at a discount of 25% on the list price.What is his profit percentage ?

 A) 10% B) 15% C) 20% D) 25%

Explanation:

Let the list price be Rs.100.

Therefore,the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15.

Therefore, his percentage is $\inline \frac{15}{60}\times 100$ = 25%

Subject: Profit and Loss - Quantitative Aptitude - Arithmetic Ability

9

A shopkeeper sells one-third of his goods at a profit of 10%, another one-third at a profit of 20%, and the rest at a loss of 6%.What is his overall profit percentage ?

 A) 6% B) 8% C) 10% D) 12%

Explanation:

Let the shopkeeper buy 300g for Rs.300. Now he sells 100g for Rs.110, another 100g for Rs120, and the rest 100g for Rs94.

Therefore, the total amount he receives = Rs.110 + Rs.120 + Rs.94 = 324.

Therefore, the shopkeeper spends Rs.300 and gets back Rs.324.

Therefore, his profit percentage = $\inline \frac{24}{300}\times 100$ % = 8%

Subject: Profit and Loss - Quantitative Aptitude - Arithmetic Ability

2

By selling an article at Rs.800, a shopkeeper makes a profit of 25%.At what price should he sell the article so as to make a loss of 25%?

 A) Rs.720 B) Rs.640 C) Rs.540 D) Rs.480

Explanation:

SP = Rs.800 ; Profit = 25%

$\inline \fn_cm CP = SP x \left [ \frac{100}{(100+P)} \right ]=800x\left [ \frac{100}{100+25} \right ]=Rs.640$

Now, CP = Rs.640

Loss = 25% = 25% of Rs.640 = Rs.160

Thus, SP = CP - Loss = Rs.640 - Rs.160 = Rs.480

Subject: Profit and Loss - Quantitative Aptitude - Arithmetic Ability

2

A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes?

 A) 4% B) 5% C) 6% D) 8%

Explanation:

SP of first article = Rs.1000

Profit = 20%

$\inline \fn_cm CP=SP\times [\frac{100}{(100+P)}]=Rs.\frac{2500}{3}$

SP of Second Article = Rs.1000

Loss = 20%

$\inline \fn_cm CP=SP\times [\frac{100}{(100-L)}]=Rs.1250$

So, Total SP = Rs.2000; Total CP = Rs.6250/3

As the CP is more than SP, he makes a loss.

Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3)

So, Loss Percent = $\inline \fn_cm \left [ \frac{\frac{250}{3}}{\frac{6250}{3}} \right ]x100$= 4%