3
Q:

A child has three different kinds of chocolates costing  Rs.2, Rs.5, Rs.10.  He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be  atleast one chocolate of each kind?

A) 22 B) 19
C) 17 D) 15

Answer:   C) 17

Explanation:

Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.

Thus,          2 x 5 + 5 x 2 =Rs.20

Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.

Thus minumum number of chocolates = 5 + 2 + 10 = 17

Q:

The third proportional to 9 and 12 is ?

A) 14 B) 16
C) 18 D) 20
 
Answer & Explanation Answer: B) 16

Explanation:

Let the third proportion to 9 & 12 be 'x'.

=> 9:12 = 12 :p

=> p = 12x12/9 = 16.

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1 19
Q:

64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3 ?

A) 168 B) 201
C) 147 D) 154
 
Answer & Explanation Answer: A) 168

Explanation:

Let us say x boys and x girls joined the group.

(64 + x)/(40 + x) = 4/3

192 + 3x = 160 + 4x => x = 32

Number of members in the group = 64 + x + 40 + x

= 104 + 2x = 168.

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0 44
Q:

In an exam, a candidate secured 504 marks out of the maximum mark of 'M'. If the maximum mark 'M' is converted into 800 marks, he would have secured 384 marks. What is the value of 'M' ?

A) 910 B) 1000
C) 970 D) None of the above
 
Answer & Explanation Answer: D) None of the above

Explanation:

504/M = 384/800

(504 x 800) / 384 = M

M = 1050

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1 73
Q:

In a class of 39 students the ratio of boys and girls is 2 : 1. Radhika ranks 15th among all the students from top and 8th among girls from bottom. How many boys are there below Radhika ?

A) 9 B) 17
C) 11 D) 15
 
Answer & Explanation Answer: B) 17

Explanation:

Total student= 39, boys : girls = 2:1, hence no of boys= 2/3(39)= 26
num of girls= 1/3(39) = 13 , since radhika ranked 15 among 39 student from top
and ranked 8 among girls from bottom , this means 7 girls are below radhika, rest 13-9= 5 girls are above her, now from 14 toper 5 are girls hence 14-5=9 boys.
Hence num of boys below radhika are 26-9=17

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4 243
Q:

The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ?

A) Rs. 5500 B) Rs. 6000
C) Rs. 6200 D) Rs. 6350
 
Answer & Explanation Answer: B) Rs. 6000

Explanation:

The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?
Ratio of increase of wages = 22:25
Ratio of decrease of labourers = 15:11
Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275
Final bill = Rs. 5000
For 275 ratio wages = Rs. 5000
For 1 ratio wages = 5000/275
For 330 ratio wages = 5000/275 x 330 = Rs. 6000

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1 168