A) 4:5 | B) 3:2 |

C) 3:5 | D) 2:3 |

Explanation:

Concentration of petrol in A B C

1/2 3/5 4/5

Quantity of petrol taken from A = 1 litre out of 2 litre

Quantity of petrol taken from B = 1.8litre out of 3 litre

Quantity of petrol taken from C = 0.8 litre out of 1 litre

Therefore, total petrol taken out from A, B and C = 1+1.8+0.8 =3.6 litres

So, the quantity of kerosen =(2+3+1) - 3.6 =2.4 litre

Thus, the ratio of petrol to kerosene = 3.6/2.4 = 3/2

A) Rs. 159 | B) Rs. 96 |

C) Rs. 147 | D) Rs. 105 |

Explanation:

K : L : M = 100 : 45 : 30

= 20 : 9 : 6

Given L share is 27

=> 9 ------ 27

35 ------ ?

=> 105

A) 4:5 | B) 6:5 |

C) 3:2 | D) 1:3 |

A) 7 : 9 | B) 9 : 7 |

C) 7 : 4 | D) 7 : 10 |

Explanation:

Given 5:6 :: 7:10 :: 6:5

We know that compound ratio is calculated as

a:b :: c:d :: e:f

(axcxe):(bxdxf)

=> (5x7x6):(6x10x5)

=> (210):(300)

= 7:10

A) 200, 400 | B) 100, 300 |

C) 100, 200 | D) 150, 200 |

Explanation:

The incomes of A and B be 3P and 4P.

Expenditures = Income - Savings

(3P - 100) and (4P - 100)

The ratio of their expenditure = 1:2

(3P - 100):(4P - 100) = 1:2

2P = 100 => P = 50

Their incomes = 150, 200

A) 693 | B) 741 |

C) 528 | D) 654 |

Explanation:

Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)

= (1200)(30)(3) kg.

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k

As the same provisions are available

=> (1200)(30)(3) = (1200 + x)(25)(2.5)

x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.