11
Q:

The incomes of two persons A and B are in the ratio 3 : 4. If each saves Rs.100 per month, the ratio of their expenditures is Rs. 1 : 2. Find their incomes.

A) Rs. 100 and Rs.150 B) Rs. 150 and Rs.200
C) Rs.200 and Rs.250 D) Rs.250 and Rs.300

Answer:   B) Rs. 150 and Rs.200



Explanation:

Let the incomes of A and B be 3P and 4P.

If each saves Rs. 100 per month, then their expenditures = Income - savings = (3P - 100) and (4P - 100).

 

The ratio of their expenditures is given as 1 : 2.

Therefor, (3P - 100) : (4P - 100) = 1 : 2

Solving, We get P = 50. Substitute this value of P in 3P and 4P.

Thus, their incomes are : Rs.150 and Rs.200

Q:

The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop? 

A) 444 B) 344
C) 244 D) 144
 
Answer & Explanation Answer: D) 144

Explanation:

Given ratio of pens and pencils = 3 :2

Number of Pens = 3x

Number of Pencils = 2x

Average number of pencils & Pens = 3x + 2x2 = 180

5x = 360

=> x = 72


Hence, the number of pencils = 2x = 72 x 2 = 144.

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8 600
Q:

The ratio of boys and girls in a school is 9:5.If the total number of students in the school is 1050.Then number of boys is

Answer

Let the ratio be 'R'


Total number of students = 1050


Then,


9R + 5R = 1050


14R = 1050


=> R = 75


 


Hence, the number of boys = 9R = 9 x 75 = 675

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7 1040
Q:

3 : 12 :: 5 : ?

A) 17 B) 30
C) 26 D) 32
 
Answer & Explanation Answer: B) 30

Explanation:

332 + 3 = 12552 + 5 = 30

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9 946
Q:

The ratio of the incomes of Pavan and Amar is 4 : 3 and the ratio of their expenditures are 3:2. If each person saves Rs. 1889, then find the income of Pavan?

A) 6548 B) 5667
C) 7556 D) 8457
 
Answer & Explanation Answer: C) 7556

Explanation:

Let ratio of the incomes of Pavan and Amar be 4x and 3x

and Ratio of their expenditures be 3y and 2y

4x - 3y = 1889 ......... I

and

3x - 2y = 1889 ...........II

I and II

y = 1889

and x = 1889

Pavan's income = 7556

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9 1332
Q:

Maneela lent Rs. 8000 partly at the rate of 5% and partly at the rate of 6% per annum simple interest. The total interest she get after 2 years is Rs. 820, then in which ratio will Rs. 8000 is to be divided?

A) 7:1 B) 13:5
C) 15:7 D) 2:7
 
Answer & Explanation Answer: A) 7:1

Explanation:

Maneela lent Rs. 8000 in two parts,

Capture1510815753.JPG image

 

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11 1213
Q:

The ratio of male and female in a city is 7 : 8 respectively and percentage of children among male and female is 25 and 20 respectively. If number of adult females is 156800, what is the total population of the city?

A) 4,12,480 B) 3,67,500
C) 5,44,700 D) 2,98,948
 
Answer & Explanation Answer: B) 3,67,500

Explanation:

Let the total population be 'p'

Given ratio of male and female in a city is 7 : 8

In that percentage of children among male and female is 25% and 20%

=> Adults male and female % = 75% & 80%

But given adult females is = 156800

=> 80%(8p/15) = 156800

=> 80 x 8p/15 x 100 = 156800

=> p = 156800 x 15 x 100/80 x 8

=> p = 367500

Therefore, the total population of the city = p = 367500

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14 1485
Q:

Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ?

A) 11 & 17 B) 7 & 17
C) 9 & 21 D) 13 & 23
 
Answer & Explanation Answer: C) 9 & 21

Explanation:

Let the two numbers be x and y

Given x : y = 3 : 7 .....(1)

Now, x+6 : y+6 = 5 : 9 .....(2)

From (1), x = 3y/7

From (2), 5y - 9x = 24

=> 5y - 9(3y/7) = 24

=> y = 21

=> From(1), x = 9

Hence, the two numbers be 9 and 21

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11 1249
Q:

In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?

A) 175 B) 165
C) 155 D) 145
 
Answer & Explanation Answer: C) 155

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x 

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

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19 1376