In an examination, a student scores 4 marks for every correct answer and loses I mark for every wrong answer. If he attempts in all 60 questions and secures 130 marks, the number of questions he attempts correctly, is:
Let the number of correct answers be X.
Number of incorrect answers = (60 – X).
4x – (60 – x) = 130
=> 5x = 190 => x = 38
Simplify the following equation.
Hence the answer is 1.5+4.7+3.8=10
38% of 7500 + ?% of 375 = 50% of 6000