15
Q:

# A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 59.29, the number of the member is the group is:

 A) 57 B) 67 C) 77 D) 87

Answer:   C) 77

Explanation:

Money collected = (59.29 x 100) paise = 5929 paise.

Number of members = $\sqrt{5929}$ = 77.

Q:

If (89)2 is added to the square of a number, the answer so obtained is 16202. What is the (1/26) of that number?

 A) 5.65 B) 2.7 C) 3.5 D) 6.66

Answer & Explanation Answer: C) 3.5

Explanation:

Let the number is = x

(89)2 + x2 = 16202

x2 = 8281

x = 91

=> (1/26) of 91 = 3.5

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7 222
Q:

What should come in place of x in the following equation?

 A) 13 B) 12 C) 17 D) 16

Answer & Explanation Answer: B) 12

Explanation:

Then x2 = $\sqrt{162}x\sqrt{128}$

= Sqrt of 82 x 62 x 32

= 8 x 6 x 3

x2  = 144.

x  = 12.

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5 254
Q:

Find the value of $\sqrt{\frac{\mathbf{1}\mathbf{.}\mathbf{21}\mathbf{x}\mathbf{0}\mathbf{.}\mathbf{9}}{\mathbf{1}\mathbf{.}\mathbf{1}\mathbf{x}\mathbf{0}\mathbf{.}\mathbf{11}}}$?

 A) 0 B) 1 C) 3 D) 5

Answer & Explanation Answer: C) 3

Explanation:

Given   $\sqrt{\frac{1.21x0.9}{1.1x0.11}}$

$\sqrt{\frac{1.21x100x0.9x10}{1.1x10x0.11x100}}$

$\sqrt{9}$

= 3.

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4 446
Q:

If  then find the value of ${\mathbit{x}}^{\mathbf{3}}\mathbf{-}\mathbf{6}{\mathbit{x}}^{\mathbf{2}}\mathbf{+}\mathbf{6}\mathbit{x}$ ?

 A) 1 B) 2 C) 3 D) 4

Answer & Explanation Answer: B) 2

Explanation:

Given that

So x - 2 =

Now cubing on both sides, we get

=>

Therefore,

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5 390
Q:

If

 A) 3/4 B) 4/3 C) 3/5 D) 5/3

Answer & Explanation Answer: B) 4/3

Explanation:

By simplifying, we get 4/3

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3 878
Q:

If x =

 A) 3sqrt{3} B) 8sqrt{3} C) 14 D) 14+8sqrt{3}

Answer & Explanation Answer: C) 14

Explanation:
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29 1392
Q:

 A) 3 B) 3sqrt{2} C) 6 D) None of these

Answer & Explanation Answer: D) None of these

Explanation:
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13 1329
Q:

If

 A) a=-11,b=-6 B) a=-11,b=6 C) a=11,b=-6 D) a=11,b=6

Answer & Explanation Answer: C) a=11,b=-6

Explanation:
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5 950