6
Q:

# In a public bathroom there are n taps 1,2,3...n. Tap1 and Tap2 take equal time to fill the tank while Tap3 takes half the time taken by Tap2 and Tap4 takes half the time taken by Tap3. Similarly each next number of tap takes half the time taken by previous number of Tap i.e, K-th  Tap takes half the time taken by (K-1)th Tap.If the 10th tap takes 2 hours to fill the tank alone then what is the ratio of  efficiency of 8th tap and 12th tap, respectively?

 A) 4:1 B) 5:3 C) 16:1 D) 1:16

Explanation:

Time taken by 8th tap = $\inline&space;2\times&space;2\times&space;2$ = 8 hours

and time taken by 12th tap = $\inline&space;2\times&space;\frac{1}{2}\times&space;\frac{1}{2}$ = $\inline&space;\frac{1}{2}$ hour

Ratio of time taken by 8th 8th tap and 12th tap = $\inline&space;8:\frac{1}{2}$ =16:1

Therefore, Ratio of efficiencies of 8th tap and 12th tap =1:16

Q:

P alone can do a piece of work in 24 days. The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work. How many days are required to complete by P and Q working together ?

 A) 9 3/5 days B) 7 days C) 6 3/7 days D) 8 days

Explanation:

Let the total work be 'W'

As per the given information,

P can complete the work 'W' in 24 days.

=> one day work of P = W/24

And also given that,

The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work

=> PW/3 = QW/2

=> P's

1 day =    W/24

?    =      W/3

=>  ?  = 24W/3W  = 8

=> QW/2 = 8 days

=> Q alone can complete the work W in 16 days

=> P + Q can complete the work in

1/24 + 1/16 = 5/48

=> 48/5 days = 9 3/5 days.

10 123
Q:

P can do a piece of work in 5 less days than Q. If both of them can do the same work in $\inline \fn_jvn 11\tfrac{1}{9}$ days, in how many days will Q alone do the same work  ?

 A) 24 days B) 25 days C) 20 days D) 19 days

Explanation:

Let Q complete that work in 'L' days

=> $\inline \fn_jvn \frac{1}{L}+\frac{1}{L-5}=\frac{9}{100}$

=> $\inline \fn_jvn 9L^{2}-245L+500=0$

L = 25 days.

7 130
Q:

Time taken by P alone to finish a work is 50% more than the time taken by P and Q together. Q is thrice as efficient as R. If Q and R together can complete the work in 22.5 days, then how many days will P alone take to complete the work ?

 A) 17 days B) 11 days C) 15 days D) 16 days

Explanation:

We know that Time is inversely proportional to Efficiency

Here given time ratio of P & P+Q as

P/P+Q = 150/100 = 3:2

Efficiency ratio of P & Q as

P:Q = 2:1 ....(1)

Given Efficiency ratio of Q & R as

Q:R = 3:1 ....(2)

From (1) & (2), we get

P:Q:R = 6:3:1

P alone can finish the work in

22.5(3+1)/6 = 15 days.

5 304
Q:

A town having teenagers(boys & girls) of 5000 requires 150 litre of water per head. It has a tank measuring 20 m × 15 m × 5 m. The water of this tank will sufficient for ____ days.

 A) 8 B) 6 C) 4 D) 2

Explanation:

Total Water reqduired = 5000 × 150 lit

= 750,000 litres = 750 cu.m.

Volume of tank = 20 × 15 × 5 = 1500 Cu.m.

Number of days required =1500/750 = 2 days.

6 182
Q:

Priya can do a work in 16 days. In how many days will the work be completed by Sai, if the efficiency of Sai is 60% more than that of Priya ?

 A) 8 days B) 12 days C) 14 days D) 10 days

Explanation:

Ratio of efficiencies of Priya and Sai is

Sai : Priya = 160 : 100 = 8 : 5

Given Priya completes the work in 16 days

Let number of days Sai completes the work be 'd'

=> 5×16 = 8×d

d = 10 days.

Therefore, number of days Sai completes the work is 10 days.