A, B and C can complete a piece of work in 24,6 and 12 days respectively.Working together, they will complete the same work in:
(A+B+C)'s 1 day's work =
so, A,B and C together will complete the work in 24/7 days.
A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in ?
Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.
Sixty men can stitch 150 shirts in 30 days working 8 hours a day. In how many days can 35 men stitch 200 shirts working 6 hours a day ?
We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)(60 x 30 x 8)/ 150 = (35 x D2 x 6) / 200 D2 = (60 x 30 x 8 x 200) / (150 x 35 x 6) => D2 = 91.42 days =~ 91.5 days.
A can complete a piece of work in 12 days and B is 60% more efficient than A. In how many days B will complete the same work ?
Ratio of times taken by A and B = 160 : 100A can do the work in 12 daysLet B can do the work in "D" days=> 160:100 = 12 : D=> D = 12 x 100/160 = 7.5 hrs
A can finish a work in 18 days and B can do the same work in half the time taken by A. then, working together, what part of the same work they can finish in a day ?
A can do the work = 18 daysB can do the work = 18/2 = 9 days(A + B)'s 1 day work = 1/18 + 1/9 = 1/6=> In 3 days = 3x1/6 = 1/2 work is completed.
10 boys can complete a work in 7 days and 10 girls take 14 days to complete the work. How many days will 5 boys and 10 girls take to complete the work ?
1 boy's 1 day work = 1/70 1 girl's 1 day work = 1/140 (5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7
5 boys and 10 girls will complete the work in 7 days.
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