A) 8 hrs 45 min | B) 8 hrs 42 min |

C) 8 hrs | D) 8 hrs 34 min |

Explanation:

Number of pages typed by Adam in 1 hour = 36/6 = 6

Number of pages typed by Smith in 1 hour = 40/5 = 8

Number of pages typed by both in 1 hour = (6 + 8) = 14

Time taken by both to type 110 pages = (120 * 1/14) = $8\frac{4}{7}$ = 8 hrs 34 min.

A) 24 days | B) 25 days |

C) 20 days | D) 19 days |

Explanation:

Let Q complete that work in 'L' days

=> $\frac{1}{L}+\frac{1}{L-5}=\frac{9}{100}$

=> $9{L}^{2}-245L+500=0$

L = 25 days.

A) 17 days | B) 11 days |

C) 15 days | D) 16 days |

Explanation:

We know that Time is inversely proportional to Efficiency

Here given time ratio of P & P+Q as

P/P+Q = 150/100 = 3:2

Efficiency ratio of P & Q as

P:Q = 2:1 ....(1)

Given Efficiency ratio of Q & R as

Q:R = 3:1 ....(2)

From (1) & (2), we get

P:Q:R = 6:3:1

P alone can finish the work in

22.5(3+1)/6 = 15 days.

A) 8 | B) 6 |

C) 4 | D) 2 |

Explanation:

Total Water reqduired = 5000 × 150 lit = 750,000 litres = 750 cu.m.

Volume of tank = 20 × 15 × 5 = 1500 Cu.m.

Number of days required =1500/750 = 2 days.

A) 8 days | B) 12 days |

C) 14 days | D) 10 days |

Explanation:

Ratio of efficiencies of Priya and Sai is

Sai : Priya = 160 : 100 = 8 : 5

Given Priya completes the work in 16 days

Let number of days Sai completes the work be 'd'

=> 5×16 = 8×d

d = 10 days.

Therefore, number of days Sai completes the work is 10 days.

A) 50 | B) 100 |

C) 70 | D) 35 |

Explanation:

Let the Efficiency of pavan be E(P)

Let the Efficiency of sravan be E(S)

Here Work W = LCM(25,20) = 100

Now, E(P+2S) = 100/25 = 4 ....(1)

E(2P+S) = 100/20 = 5 ....(2)

Hence, from (1) & (2) we get

E(S) = 1

=> Number of days Savan alone work to complete the work = 100/1 = 100 days.

A) 64 | B) 62 |

C) 58 | D) 56 |

Explanation:

Days remaining 124 – 64 = 60 days

Remaining work = 1 - 2/3 = 1/3

Let men required men for working remaining days be 'm'

So men required = (120 x 64)/2 = (m x 60)/1 => m = 64

Men discharge = 120 – 64 = 56 men.

A) 12 days | B) 14 days |

C) 13 days | D) 16 days |

Explanation:

Now, Total work = LCM(16, 8) = 48

A's one day work = + 48/16 = + 3

B's one day work = - 48/8 = -6

Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15

2days B joined with A in working = 2(3 - 6) = - 6

Remaining Work of building wall = 48 - (15 - 6) = 39

Now this remaining work will be done by A in = 39/3 = 13 days.

A) 3 | B) 6 |

C) 9 | D) 12 |

Explanation:

The mother completes the job in x hours.

So, the daughter will take 2x hours to complete the same job.

In an hour, the mother will complete 1/x of the total job.

In an hour, the daughter will complete 1/2x of the total job.

So, if the mother and daughter work together, in an hour they will complete 1/x + 1/2x of the job.

i.e., in an hour they will complete 3/2x of the job.

The question states that they complete the entire task in 6 hours if they work together.

i.e., they complete 1/6 th of the task in an hour.

Equating the two information, we get 3/2x = 1/6

By solving for x, we get 2x = 18 or x = 9.

The mother takes 9 hours to complete the job.