A) 8 hrs 45 min | B) 8 hrs 42 min |

C) 8 hrs | D) 8 hrs 34 min |

Explanation:

Number of pages typed by Adam in 1 hour = = 6

Number of pages typed by Smith in 1 hour = = 8

Number of pages typed by both in 1 hour = (6 + 8) = 14

Time taken by both to type 110 pages = (120 * 1/14) = 8 = 8 hrs 34 min.

A) 7 | B) 8 |

C) 9 | D) 10 |

Explanation:

As the work is same

M1D1 = M2D2

Here Let the number of men employed was M

=> 11M = 7(M+4)

=> 11M - 7M = 28

=> M = 7

A) 18 days | B) 20 days |

C) 16 days | D) 14 days |

Explanation:

(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 x 8)/4 = 20 days.

A) 1:2 | B) 1:3 |

C) 3:1 | D) 2:1 |

Explanation:

5M + 2B = 4(1M + 1B)

5M + 2B = 4M + 4B

1M = 2B

The required ratio of work done by a man and a boy = 2:1

A) 6 | B) 9 |

C) 5 | D) 7 |

Explanation:

Let 1 woman's 1 day work = x.

Then, 1 man's 1 day work = x/2 and 1 child's 1 day work x/4.

So, (3x/2 + 4x + + 6x/4) = 1/7

28x/4 = 1/7 => x = 1/49

1 woman alone can complete the work in 49 days.

So, to complete the work in 7 days, number of women required = 49/7 = 7.

A) 15 days | B) 11 days |

C) 14 days | D) 12 days |

Explanation:

9M + 12B ----- 12 days ...........(1)

12M + 12B ------- 10 days........(2)

10M + 10B -------?

108M + 144B = 120M +120B

24B = 12M => 1M = 2B............(3)

From (1) & (3)

18B + 12B = 30B ---- 12 days

20B + 10B = 30B -----? => 12 days.