A) 8 hrs 45 min | B) 8 hrs 42 min |

C) 8 hrs | D) 8 hrs 34 min |

Explanation:

Number of pages typed by Adam in 1 hour = 36/6 = 6

Number of pages typed by Smith in 1 hour = 40/5 = 8

Number of pages typed by both in 1 hour = (6 + 8) = 14

Time taken by both to type 110 pages = (120 * 1/14) = $8\frac{4}{7}$ = 8 hrs 34 min.

A) 87.5 | B) 89 |

C) 91.5 | D) 93.5 |

Explanation:

We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)

(60 x 30 x 8)/ 150 = (35 x D2 x 6) / 200

D2 = (60 x 30 x 8 x 200) / (150 x 35 x 6) => D2 = 91.42 days =~ 91.5 days.

A) 8.7 hrs | B) 5.2 hrs |

C) 5 hrs | D) 7.5 hrs |

Explanation:

Ratio of times taken by A and B = 160 : 100

A can do the work in 12 days

Let B can do the work in "D" days

=> 160:100 = 12 : D

=> D = 12 x 100/160 = 7.5 hrs

A) Total work | B) One-fourth work |

C) Half work | D) Two-third work |

Explanation:

A can do the work = 18 days

B can do the work = 18/2 = 9 days

(A + B)'s 1 day work = 1/18 + 1/9 = 1/6

=> In 3 days = 3x1/6 = 1/2 work is completed.

A) 13 days | B) 10 days |

C) 7 days | D) 16 days |

Explanation:

1 boy's 1 day work = 1/70

1 girl's 1 day work = 1/140

(5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7

5 boys and 10 girls will complete the work in 7 days.

A) 9 days | B) 11 days |

C) 13 days | D) 15 days |

Explanation:

Ratio of times taken by A and B = 100 : 130 = 10 : 13.

Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x => x = ( 23 x 13/10 ) => x = 299 /10.

A's 1 day's work = 1/23 ;

B's 1 day's work = 10/299 .

(A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 .

Therefore, A and B together can complete the work in 13 days.

A) 10 days | B) 14 days |

C) 11 days | D) 9 days |

Explanation:

For 30 days he receives

30 x 25 = 750

Actually he gets 425

Therefore, Fine is 750 - 425 = 325

=> No of days absent = 325/(25+7.50)= 10

A) 40 days | B) 36 days |

C) 32 days | D) 34 days |

Explanation:

Let 1 man's 1 day work = x and 1 woman's 1 day work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10

Solving these two equations, we get:

x = 11/400 and y = 1/400

10 woman's 1 day work = (1/400 x 10) = 1/40.

Hence, 10 women will complete the work in 40 days.

A) 7 | B) 8 |

C) 9 | D) 10 |

Explanation:

As the work is same

M1D1 = M2D2

Here Let the number of men employed was M

=> 11M = 7(M+4)

=> 11M - 7M = 28

=> M = 7