A) 15 | B) 30 |

C) 25 | D) 10 |

Explanation:

Combined efficiency of all the three boats = 60 passenger/trip

Now, consider option(a)

15 trips and 150 passengers means efficiency of B1 = 10 passenger/trip

which means in carrying 50 passengers B1 must has taken 5 trips. So the rest trips equal to 5 (10-5 = 5) in which B2 and B3 together carried remaining 250 (300 - 50 = 250) Passengers.

Therefore the efficiency of B2 and B3 = 250/5 = 50 passenger/trip

Since, the combined efficiency of B1, B2 and B3 is 60. Which is same as given in the first statement hence option(a) is correct.

A) 16 days | B) 72/5 days |

C) 15 days | D) 96/5 days |

Explanation:

Work done by Shyam and Rahim in 8 days **= 8/32 = 1/4**

Remaining work to be done by Shyam and Ram **= 1 - 1/4 = 3/4**

Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days.

One day work of Ram and Shyam **= (1/32 - 1/48) + 1/24 = 5/96**

Hence, the total work can be done by Shyam and Ram together in **96/5 days.**

Therefore, remaining work 3/4 can be done by them in **3/4 x 96/5 = 72/5 = 14.4 days.**

A) 38 | B) 72 |

C) 36 | D) 76 |

Explanation:

Given 4men, 12 women and 20 children work for 2 days.

Workdone for 2 days by 4men, 12 women and 20 children = $\frac{\mathbf{4}\mathbf{}\mathbf{x}\mathbf{}\mathbf{2}}{\mathbf{6}\mathbf{}\mathbf{x}\mathbf{}\mathbf{12}}\mathbf{}\mathbf{+}\mathbf{}\frac{\mathbf{12}\mathbf{}\mathbf{x}\mathbf{}\mathbf{2}}{\mathbf{8}\mathbf{}\mathbf{x}\mathbf{}\mathbf{18}}\mathbf{}\mathbf{+}\mathbf{}\frac{\mathbf{20}\mathbf{}\mathbf{x}\mathbf{}\mathbf{2}}{\mathbf{18}\mathbf{}\mathbf{x}\mathbf{}\mathbf{10}}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{1}}{\mathbf{2}}$

Therefore, remaining work = 1 - $\frac{1}{2}$ = $\frac{1}{2}$

To complete the same work by only men in 1 day,

We know that M1 x D1 = M2 x D2

Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1

12 x 6 = M x 1

=> M = 12 x 6 = 72

=> But the remaining work = 1/2

Men required => 1/2 x 72 = 36

Only men required to Complete the remaining work in 1 day = 36.

A) 7 | B) 8 |

C) 9 | D) 6 |

Explanation:

Given (3 Men + 4 Women + 6 Children) -----> 9 days

But W = 2M and C = M/2

Now, convert Men and Children into Women by

$\mathbf{3}\frac{\mathbf{W}}{\mathbf{2}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{4}\mathbf{W}\mathbf{}\mathbf{+}\mathbf{}\mathbf{6}\frac{\mathbf{W}}{\mathbf{4}}\phantom{\rule{0ex}{0ex}}\mathbf{=}\mathbf{}\mathbf{}\frac{\mathbf{3}}{\mathbf{2}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{4}\mathbf{}\mathbf{+}\mathbf{}\frac{\mathbf{3}}{\mathbf{2}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{7}\mathbf{}\mathbf{Women}$

Therefore, * 7 women *alone can complete this work in 9 days.

A) 35/4 days | B) 17.5 days |

C) 19 3/4 days | D) 37/3 days |

Explanation:

Let the number of days be 'p'

As the work is same, we know that

$\mathbf{M}\mathbf{1}\mathbf{}\mathbf{x}\mathbf{}\mathbf{D}\mathbf{1}\mathbf{}\mathbf{x}\mathbf{}\mathbf{H}\mathbf{1}\mathbf{}\mathbf{=}\mathbf{}\mathbf{M}\mathbf{2}\mathbf{}\mathbf{x}\mathbf{}\mathbf{D}\mathbf{2}\mathbf{}\mathbf{x}\mathbf{}\mathbf{H}\mathbf{2}$

Where M = Men, D = Days, H = Hours per day

Here M1 = 9, D1 = 15, H1 = 7

M2 = 6, D2 = p, H2 = 9

=> 9 x 15 x 7 = 6 x p x 9

=> p = 35/2 = 17.5 days.

A) 45 | B) 44 |

C) 46 | D) 47 |

Explanation:

Here given soldier shots 7 shots in 12 min

=> 1 shot doen't take any time in 12 min

=> Only 6 shots take 12 min

12 min ------ 6 shots

90 min ------ ? shots

=> 90 x (6/12) = 45

Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.

A) 111 | B) 117 |

C) 123 | D) 139 |

Explanation:

We know that, $\frac{\mathbf{M}\mathbf{1}\mathbf{}\mathbf{\times}\mathbf{}\mathbf{D}\mathbf{1}}{\mathbf{W}\mathbf{1}}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{M}\mathbf{2}\mathbf{}\mathbf{\times}\mathbf{}\mathbf{D}\mathbf{2}}{\mathbf{W}\mathbf{2}}$

Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845

$\frac{\mathbf{1}\mathbf{}\mathbf{\times}\mathbf{}\mathbf{6}}{\mathbf{1}}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{M}\mathbf{}\mathbf{\times}\mathbf{}\mathbf{90}}{\mathbf{1845}}$

=> **M = 123**

A) 4 days | B) 6 days |

C) 7 days | D) 5 days |

Explanation:

Given that

6 men and 8 boys can do a piece of work in 10 days

26 men and 48 boys can do the same in 2 days

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.

A) 36 | B) 32 |

C) 22 | D) 28 |

Explanation:

Let the total women in the group be **'W'**

Then according to the given data,

**W x 20 = (W-12) x 32**

=> W = 32

*Therefore, the total number of women in the group =* 32