Quantitative Aptitude - Arithmetic Ability Questions

Let Veena paid x,
so Akshitha paid 2x/3 , and Lasya paid 2x,
So total bill paid is given by
x+(2x/3) +2x = 1, we get
i.e. x = 3/11

Let the number of boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35
So 30x + 35 + 31(x + 1) = > x = 4.

Speed in downstream = 96/8 = 12 kmph

Speed of current = 4 km/hr

Speed of the boatman in still water = 12 – 4 = 8 kmph

Speed in upstream = 8 – 4 = 4 kmph

Time taken to cover 8 km upstream = 8/4 = 2 hours.

Total cost of 4 cars =  1+2 = 3 lakh

Total S.P of 4 cars = 3 x 1.5 = 4.5 lakh   (Since S.P = 100 + Gain%100 x C.P)

 S.P of 1 car = 1.2 lakh 

S.P of rest 3 cars = 4.5 - 1.2 = 3.3 lakh

 Average S.P of all the 3 cars = 1.1 lakh

It is given that efficiency ratio =3:1

so time ratio will be 1:3 (since work is same)

Also given that time diff = 32 days. ratio difference = 3-1 =2 

2 ratio = 32 days

1 ratio = 16 days.

So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.

Total work = LCM of 16 and 48 = 48.

Total time = Total work/Total efficiency 

ie; 48/4= 12 days.

Total employees = 25-10×2010=30

 Hence number of educated employees  = 30-20 = 10

Here always remember, when ever x% loss,
it means S.P. = (100 - x)% of C.P
when ever x% profit,
it means S.P. = (100 + x)% of C.P

So here will be (100 - x)% of C.P.
= 80% of 1200
= (80/100) * 1200
= 960

Let the number be x. Then, 15x - x = 196 <=> 14x = 196 => x = 14..