6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ?

A) 18 days	B) 20 days
C) 16 days	D) 14 days

Answer & Explanation Answer: B) 20 days

Explanation:

(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 1m = 3w

5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 x 8)/4 = 20 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

9 17383

Q:

If the cost price of a certain object doubles, then the loss gets tripled of what it was initially. The initial loss % was ?

A) 0 %	B) 25 %
C) 75 %	D) 50 %

Answer & Explanation Answer: D) 50 %

Explanation:

Let the cost price be x and selling price be y.
Loss = x – y

When the cost price doubles, the loss gets tripled.
So it becomes like this, 2x – y = 3(x-y)

=> x = 2y

Loss % = (loss/ C.P) x 100 = [(2y-y)/2y] x 100= 50 %

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Filed Under: Profit and Loss
Exam Prep: CAT
Job Role: Bank PO

24 17379

Q:

Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together?

A) 6	B) 8
C) 9	D) 12

Answer & Explanation Answer: B) 8

Explanation:

$\begin{matrix} A m i t & B h a r a t \\ N o . o f D a y s & 45 & 40 \\ E f f i c i e n c y & 2.22 P e r c e n t (= \frac{1}{45}) & 2.5 P e r c e n t (= \frac{1}{40}) \end{matrix}$

Amit did the work in 56 days = $56 \times \frac{1}{45 \times 2} = \frac{28}{45}$

Therefore, Rest work 17/45 was done by Amit and Bharath = $\frac{\frac{17}{45}}{\frac{17}{360}}$ = 8 days

( since Amit and Bharath do the work in one day = $\frac{1}{45} + \frac{1}{40} = \frac{17}{360}$ )

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

30 17375

Q:

Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is

A) 12	B) 32
C) 42	D) 52

Answer & Explanation Answer: C) 42

Explanation:

required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm

= 196 - 154 = 42 sq.cm.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

11 17326

Q:

A cuboidal block 6cm x 9cm x 12cm is cut up into an exact number of equal cubes.The least possible number of equal cubes will be

A) 6	B) 9
C) 24	D) 30

Answer & Explanation Answer: C) 24

Explanation:

Volume of block=(6 x 9 x 12) cu.cm = 648 cu.cm

Side of largest cube = H.C.F of 6,9,12 = 3cm

Volume of the cube=(3 x 3 x 3)=27cu.cm

Number of cubes=(648/27)=24

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

18 17303

Q:

1. The simple interest on a sum of money is Rs. 50. What is the sum?
I. The interest rate is 10% p.a.
II. The sum earned simple interest in 10 years

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Given : S.I. = Rs. 50.

I gives, R = 10% p.a.

II gives, T = 10 years.

Sum = (100 x S.I)/(t x r ) = Rs.(100 x 50)/(10 x 10) = Rs.50

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Filed Under: Simple Interest
Exam Prep: GRE

4 17264

Q:

A triangle has a perimeter 13. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?

A) 4	B) 6
C) 8	D) None of the above

Answer & Explanation Answer: B) 6

Explanation:

The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers.

Option A cannot be correct because 4 would not be the longest side.(sides 4, 5, and 4)

Option B could be correct because the other two sides would be 3 and 4.

Option C cannot be correct because this third side would be greater than the sum of the other two sides.

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Filed Under: Area
Exam Prep: GRE

6 17259

Q:

Find the number of subsets of the set {1,2,3,4,5,6,7,8,9,10,11} having 4 elements.

A) 340	B) 370
C) 320	D) 330

Answer & Explanation Answer: D) 330

Explanation:

Here the order of choosing the elements doesn’t matter and this is a problem in combinations.

We have to find the number of ways of choosing 4 elements of this set which has 11 elements.

This can be done in 11 $C_{4}$ ways = 330 ways

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Filed Under: Permutations and Combinations

15 17254

Quantitative Aptitude - Arithmetic Ability Questions

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