Quantitative Aptitude - Arithmetic Ability Questions

Let the total amount be 200 {L.C.M of 40 and 50}

Chacobar C.P. = 200/50 = 4

Fivestar C.P = 200/40 = 5

Remaining Money after petrol = [200 - 200×10%] = 180

Remaining money after buying fivestars = [180 - 20×5] = 80

So number of Chacobar she can buy = 80/4 = 20

Let the second & third numbers are 2x & 3x respectively.
ATQ,
5x*6x = 4320
30*x*x = 4320
x*x = 144
x=12
Hence, second number = 5x = 5*12 = 60
Third number = 6x = 6*12 = 72
Ratio of first & second number = ¾
Hence, first number = ( ¾)*60 = 45
Sum of these 3 numbers = 60+72+45 = 177

Let the cost price of the article be 'P'

Then from given data,

$$\begin{gathered} P + 28P100 = 4544 \\ => 128P = 454400 \\ => P = 3550 \end{gathered}$$

Hence, the cost price of the article = P = Rs. 3550

Let the monthly salary of Shankar be = Rs.x
Amount invested on expenditure = 25% = x/4;
Remaning amount = 3x/4;
Amount invested on children education = 20% i.e = 3x/20;
Remaining amount = 3x/4 - 3x/20 = 3x/5;
Remaining amount invested in three different schemes i.e is 1/3(3x/5)
=> x/5 = 5600
Therefore x = 28000
Hence, Monthly salary of Shankar is Rs. 28,000.

i=j/m

The monthly payment will be=PV*I

Time taken to fill 2/7 = 1
Then to fill full 1 = ?
? = 1/(2/7) = 7/2 minutes.

The following arrangements satisfy all 3 conditions.

Arrangement 1: 3 books in a row; 12 rows.

Arrangement 2: 4 books in a row; 9 rows.
Arrangement 3: 6 books in a row; 6 rows.
Arrangement 4: 9 books in a row; 4 rows.
Arrangement 5: 12 books in a row; 3 rows.

Therefore, the possible arrangements are 5.

Total number of possible ways = 

9C5 = 9 x 8 x 7 x 6 x 55 x 4 x 3 x 2 x 1 = 126

Number of favorable cases = 

$$\begin{gathered} 4C2 x 5C3 + 4C3 x 5C2 + 4C4 x 5C1 \\ 4 x 32 x 1 x 5 x 4 x 33 x 2 x 1 + 4 x 3 x 23 x 2 x 1 x 5 x 4 2 x 1 + 1 x 5 \\ = 6 x 10 + 4 x 10 + 5 \\ = 60 + 40 + 5 \\ = 105 \end{gathered}$$

Therefore, required probability = 105/126 = 5/6