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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

If length of a rectangle is decreased by 6 cm we get a square and the area of square formed is 252 cm2 less than the area of square formed when breadth of the original rectangle is increased by 6 cm. Find the perimeter of the rectangle.

A) 66 cm B) 88 cm
C) 80 cm D) 72 cm
 
Answer & Explanation Answer:

Explanation:

Let length and breadth of rectangle be L cm
and B cm respectively So, ATQ
Area1= (L-6)×B
But this is square, so L-6=B
Area1= (L-6) × (L-6)
Case 2, Area2= L × (B+6),
L=B+6
So, Area2= L × L,
Given, Area2-Area1= 252(L)2-(L-6)2=252
Solving this, L= 24
B= 18
Perimeter= 2(L+B)= 2(24+18)= 84 cm

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

3 4034
Q:

If an article is sold at a gain of 6% instead of a loss of 6% the seller gets Rs. 6 more. What is the cost price of the article?

A) Rs. 18 B) Rs. 36
C) Rs. 42 D) Rs. 50
 
Answer & Explanation Answer: D) Rs. 50

Explanation:
Let CP be Rs x
Then
1.06x–0.94x = 6
So x = Rs 50
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Filed Under: Profit and Loss
Exam Prep: Bank Exams

2 4032
Q:

In a hostel the rent per room is increased by 20%. If number of rooms in the hostel is also increased by 20% and the hostel is always full, then what is the percentage change in the total collection at the cash counter?

A) 30% B) 40%
C) 44% D) 48%
 
Answer & Explanation Answer: C) 44%

Explanation:
Let initial rent be rs 10
And initial rooms be 10
So initial collection = 10*10 = Rs 100
Now new rent = 10 + 20% of 10 = 12
New no of rooms = 10 + 20% of 10 = 12
So new collection = 12*12 = 144
% change in collection = (144-100)/100*100 = 44%
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Filed Under: Percentage
Exam Prep: Bank Exams

4 4029
Q:

A bike runs at the speed of 35 km/h when not serviced and runs at 55 km/h, when serviced. After servicing the bike covers a certain distance in 5 h. How much approximate time will the bike take to cover the same distance when not serviced?

A) 8 hrs B) 7.5 hrs
C) 7 hrs D) 6.5 hrs
 
Answer & Explanation Answer: A) 8 hrs

Explanation:

Given speed of the bike after servicing = 55 kmph

Time taken for travelling some distance at 55 kmph = 5 hrs

Then, 

Distance = Speed x Time = 55 x 5 = 275 kms.

Now, 

Speed of the bike before servicing = 35 kmph

Distance = 275 kms

Now, Time = Distance/Speed = 275/35 = 7.85 hrs =~ 8 hrs.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

9 4019
Q:

In how many different ways can the letters of the word 'POVERTY' be arranged ?

A) 2520 B) 5040
C) 1260 D) None
 
Answer & Explanation Answer: B) 5040

Explanation:

The 7 letters word 'POVERTY' be arranged in 7P7 ways = 7! = 5040 ways.

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Filed Under: Permutations and Combinations
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

13 4012
Q:

Anmol soldtwo items for Rs 1000 each. On one, he gained 10% and on other, he lost 10%. How much did he gain or lose in the whole transaction?

A) profit,0.95% B) loss,1%
C) profit,10% D) loss,10%
 
Answer & Explanation Answer: B) loss,1%

Explanation:

Let the two item be A and B.

Cost price of A be x and cost price of B be y.

A sold for Rs 1000 on 10 % gain = 1.1x =1000

x= 1000/1.1 = 909.09

B sold for Rs. 1000 on 10% loss = 0.9y =1000y= 1000/0.9 = 1111.11

Total cost price of A and B = 2020.20

Selling price of A and B = 2000

Loss % = (2020.20 –2000)/2000 X 100

= 1.01 % loss

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Filed Under: Profit and Loss

3 4008
Q:

Calculate the periodic interest rate corresponding to:9.0% compounded quarterly

A) 3.45 B) 2.25
C) 5.25 D) 6.25
 
Answer & Explanation Answer: B) 2.25

Explanation:

i=j/m

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 3993
Q:

A certain sum is invested for 2 years in scheme M at 20% p.a. compound interest (compounded annually), Same sum is also invested for the same period in scheme N at k% p.a. simple interest. The interest earned from scheme M is twice of that earned from scheme N. What is the value of k?

A) 7 B) 11
C) 9 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

Interest earned in scheme M =   

P1 + 201002  - 1  = 11P25

Interest earned in scheme N =  

P x k x 2100 = Pk50

 

Now, from the given data,

 

11P25 = 2 x Pk50

k = 11

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Filed Under: Compound Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

20 3993