Quantitative Aptitude - Arithmetic Ability Questions

We Know that sum of the n natural numbers =n(n+1)2

Then sum of 50 natural numbers= 50(51)2= 1250

Average of the 50 natural numbers = 125050 = 25.5

We know Compound Interest = C.I. = P1+r100t - 1

Here P = 2680, r = 8 and t = 2

C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225

= (2680 x 52 x 2)/625

= 445.95

Compound Interest = Rs. 445.95

Here the given series 7  18  42  94  204 follows a pattern that, 

7

7 ×2+4 = 18

18 ×2+6 = 42

42 ×2+10 = 94

94 ×2+16 = 204

Similarly,

4

4 ×2+4 = 12

12 ×2+6 = 30

30 ×2+10 = 70

70 ×2+16 = 156

Hence, the value of P = 156.

F=BD×TDBD-TD=200×100200-100=200×100100=Rs.200

The given inequality is 3p - 16 < 20

For solving this inequality, follow these steps

Now add 16 on both sides

we get 3p - 16 + 16 < 20 + 16

=> 3p  < 36

Now divide the above eqn with 3 on both sides

we get, 3p/3 < 36/3

p < 12.

Cost of Rs. 100 stock   = Rs. (100-15)

Cost of Rs. 6400 stock = Rs.85100*6400 = Rs. 5440.