Quantitative Aptitude - Arithmetic Ability Questions

Q:

If √3 = 1.732, then the value of 9+233?

A) 7.169 B) 7.196
C) 5.198 D) 7.296
 
Answer & Explanation Answer: B) 7.196

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Exam Prep: Bank Exams

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Q:

If sinC - sinD = x, then value of x is

A) 2sin[(C+D)/2]cos[(C-D)/2] B) 2cos[(C+D)/2]cos[(C-D)/2]
C) 2cos[(C+D)/2]sin[(C-D)/2] D) 2sin[(C+D)/2]sin[(D-C)/2]
 
Answer & Explanation Answer: C) 2cos[(C+D)/2]sin[(C-D)/2]

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Q:

A vendor buys pens at the rate of 4 for Rs 5 and sells at the rate of 4 for Rs 3. What will be the result?

A) 40 percent gain B) 66.6 percent loss
C) 66.66 percent gain D) 40 percent loss
 
Answer & Explanation Answer: D) 40 percent loss

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

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Q:

The ratio of number of boys and girls in a class is 2 : 3. The average weight of boys and girls in the class is 18 kg and 21 kg respectively. What is the average weight (in kgs) of all the boys and girls together?

A) 99/5 B) 101/5
C) 109/6 D) 96/5
 
Answer & Explanation Answer: A) 99/5

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Filed Under: Average
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Q:

If N = 0.369369369369... and M = 0.531531531531..., then what is the value of (1/N) + (1/M)?

A) 11100/2419 B) 111/100
C) 1897/3162 D) 2419/11100
 
Answer & Explanation Answer: A) 11100/2419

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Q:

5% discount is offered on an item. By applying a promo code the customer wins 20% cash back. What is the effective discount?

A) 28.8 percent B) 24 percent
C) 25 percent D) 21 percent
 
Answer & Explanation Answer: B) 24 percent

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT

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Q:

Area of circle is equal to the area of a rectangle having perimeter of 50 cms. and length more than the breadth by 3 cms. What is the diameter of the circle?

A) 7 cms B) 21 cms
C) 28 cms D) 14 cms
 
Answer & Explanation Answer: D) 14 cms

Explanation:

Let the breadth of rectangle be x cm => Length of rectangle = (x+3) cm Now, perimeter =2(x+x+3) = 50 => 2x + 3 = 25 => x = 11 Thus, breadth = 11 cm and length = 14 cm Area of circle = Area of rectangle =>pi * r* r = 14 * 11 =>r*r = 14 * 11 * 7/22 =>r = 7 cm Diameter = 2 * 7 = 14 cm

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Q:

cot2A + cos2A is equal to

A) (cosecA -­ sinA)2(cosecA + sinA) B) (cosecA + sinA)(cosecA -­ sinA)
C) (secA + sinA)(secA -­ sinA) D) (secA -­ sinA)2(secA + sinA)
 
Answer & Explanation Answer: B) (cosecA + sinA)(cosecA -­ sinA)

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