6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If ${(x + y)}^{2} - xy = 0$ , then find the value of $\frac{x^{3} - y^{3}}{x - y}$ .

A) 2	B) 3
C) 0	D) 5

Answer & Explanation Answer: C) 0

Explanation:

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Q:

If A is 40% less than B, then B is how much percentage more than A?

A) 72.33	B) 60
C) 40	D) 66.66

Answer & Explanation Answer: D) 66.66

Explanation:

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1 57916

Q:

The length of a diagonal in cms of a rectangle of length 5 cm and width 6 cm is

A) 61	B) ±61
C) 11	D) ±11

Answer & Explanation Answer: A) 61

Explanation:

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Q:

Find the odd man out?

16, 254, 1296, 4096, 10000

A) 16	B) 254
C) 1296	D) 10000

Answer & Explanation Answer: B) 254

Explanation:

The given series 16, 254, 1296, 4096, 10000 follows a pattern that

$2^{4}, 4^{4}, 6^{4}, 8^{4}, 10^{4}, . . .$

Hence, the odd man in the series is 4 x 4 x 4 x 4 = 256 not 254.

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3 57880

Q:

If $s + \frac{1}{s} = 4$ , then the value of $s^{2} + \frac{1}{s^{2}}$

A) 14	B) 16
C) 20	D) 24

Answer & Explanation Answer: A) 14

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Q:

Which two months in a year have the same calendar?

A) October, December	B) April, November
C) June, October	D) April, July

Answer & Explanation Answer: D) April, July

Explanation:

If the period between the two months is divisible by 7, then that two months will have the same calender .

(a). Oct + Nov = 31 + 30 = 61 (not divisible by 7)

(b). Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31 = 214 (not divisible by 7)

(c). Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)

(d). Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)

Hence, April and July months will have the same calendar.

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228 57681

Q:

Simplify 5x(x + 2) + 4x

A) 5x2 + 10	B) 9x + 10
C) 5x2 - 14x	D) 5x2 + 14x

Answer & Explanation Answer: D) 5x2 + 14x

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Q:

If $\frac{7 x + 9 y}{3 x - 4 y} = \frac{19}{8}$ , then the value of x/y is

A) 148/1	B) 1/148
C) 145/1	D) 1/145

Quantitative Aptitude - Arithmetic Ability Questions

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