# Quantitative Aptitude - Arithmetic Ability Questions

## What is Quantitative Aptitude - Arithmetic Ability?

Quantitative Aptitude - Arithmetic Ability test helps measure one's numerical ability, problem solving and mathematical skills. Quantitative aptitude - arithmetic ability is found in almost all the entrance exams, competitive exams and placement exams. Quantitative aptitude questions includes questions ranging from pure numeric calculations to critical arithmetic reasoning. Questions on graph and table reading, percentage analysis, categorization, simple interests and compound interests, clocks, calendars, Areas and volumes, permutations and combinations, logarithms, numbers, percentages, partnerships, odd series, problems on ages, profit and loss, ratio & proportions, stocks &shares, time & distance, time & work and more .

Every aspirant giving Quantitative Aptitude Aptitude test tries to solve maximum number of problems with maximum accuracy and speed. In order to solve maximum problems in time one should be thorough with formulas, theorems, squares and cubes, tables and many short cut techniques and most important is to practice as many problems as possible to find yourself some tips and tricks in solving quantitative aptitude - arithmetic ability questions.

Wide range of Quantitative Aptitude - Arithmetic Ability questions given here are useful for all kinds of competitive exams like Common Aptitude Test(CAT), MAT, GMAT, IBPS and all bank competitive exams, CSAT, CLAT, SSC Exams, ICET, UPSC, SNAP Test, KPSC, XAT, GRE, Defence, LIC/G IC, Railway exams,TNPSC, University Grants Commission (UGC), Career Aptitude test (IT companies), Government Exams and etc.

• #### Volume and Surface Area

Q:

What is the next number in the following number series

3, 5, 8, 15, 28, 51, ?

 A) 98 B) 102 C) 87 D) 79

Explanation:

The given number series is

3, 5, 8, 15, 28, 51, ?

Here the pattern it follows is

3

3 + 2 = 5 ( add prime number less than 3 i.e, 2)

5 + 3 = 8 (3 is prime number less than 5)

8 + 7 = 15 (7 is prime number less than 8)

15 + 13 = 28 (13 is prime number less than 15)

28 + 23 = 51 (23 is prime number less than 28)

51 + 47 = 98 (47 is prime number less than 51)

Hence, the next number in the given number series is 98.

10 151944
Q:

Find the Odd Number in the given Number Series?

3, 6.5, 14, 29, 64, 136

 A) 14 B) 64 C) 29 D) 136

Explanation:

The Given number series 3, 6.5, 14, 29, 64, 136 follows a pattern that

3

3 x 2 + 0.5 = 6.5

6.5 x 2 + 1 = 14

14 x 2 + 2 = 30 $≠$29

30 x 2 + 4 = 64

64 x 2 + 8 = 136

Thus the wrong number in the series is 29

7 146667
Q:

If each side of a square is increased by 25%, find the percentage change in its area?

 A) 65.25 B) 56.25 C) 65 D) 56

Explanation:

let each side of the square be a , then area = $a2$

As given that The side is increased by 25%, then

New side = 125a/100 = 5a/4

New area = $5a42$

Increased area= $25a216-a2$

Increase %=$9a2/16a2*100$  % = 56.25%

984 146265
Q:

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

 A) 2/91 B) 1/22 C) 3/22 D) 2/77

Explanation:

Let S be the sample space.

Then, n(S) = number of ways of drawing 3 balls out of 15 = $15C3$  =$15*14*133*2*1$= 455.

Let E = event of getting all the 3 red balls.

n(E) = $5C3$ = $5*42*1$ = 10.

=> P(E) = n(E)/n(S) = 10/455 = 2/91.

244 146117
Q:

Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:

 A) 40 B) 80 C) 120 D) 200

Explanation:

Let the numbers be 3x, 4x and 5x.

Then, their L.C.M. = 60x.

So, 60x = 2400 or x = 40.

The numbers are (3 x 40), (4 x 40) and (5 x 40).

Hence, required H.C.F. = 40.

510 145801
Q:

A shopkeeper cheats to the extent of 10% while buying and selling, by using false weights. His total gain is.

 A) 20% B) 21% C) 22% D) 23%

Explanation:

Gain % = %

=$100+102100-100$

= 21%

728 145596
Q:

A bag contains 6 white and 4 black balls .2 balls are drawn at random. Find the probability that they are of same colour.

 A) 1/2 B) 7/15 C) 8/15 D) 1/9

Explanation:

Let S be the sample space

Then n(S) = no of ways of drawing 2 balls out of (6+4) =$10C2$ 10 =$10*92*1$ =45

Let E = event of getting both balls of same colour

Then,n(E) = no of ways (2 balls out of six) or (2 balls out of 4)

=$6C2+4C2$ = $6*52*1+4*32*1$= 15+6 = 21

Therefore, P(E) = n(E)/n(S) = 21/45 = 7/15

795 145129
Q:

Find the next number in the series

143 143 136 110 ?

 A) 91 B) 35 C) 47 D) 69

Explanation:

The next number in the series is

143 143 136 110

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