6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction ?

A) 8	B) 9
C) 10	D) 11

Answer & Explanation Answer: B) 9

Explanation:

Actual price = Rs. (25 + 2.50) = Rs. 27.50.

Saving = 2.50

Percentage Saving = [(2.50/27.50)*100]

= 2500/275

= $9 \frac{1}{11}$ %

$\approx 9$ %

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Filed Under: Percentage

111 48230

Q:

Determine the nominal rate of interest if:

The periodic rate is 0.83% per month

A) 7%	B) 8%
C) 9%	D) 10%

Answer & Explanation Answer: D) 10%

Explanation:

j=mi

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

3 47949

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) EHL	B) JMP
C) SVY	D) QTW

Answer & Explanation Answer: A) EHL

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 47799

Q:

A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

A) 10	B) 20
C) 21	D) 25

Answer & Explanation Answer: C) 21

Explanation:

Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively

Quantity of A in mixture left = $(7 x - \frac{7}{12} \times 9) = (7 x - \frac{21}{4})$ litres.

Quantity of B in mixture left = $(5 x - \frac{5}{12} \times 9) = (5 x - \frac{15}{4})$ litres.

$\frac{(7 x - \frac{21}{4})}{(5 x - \frac{15}{4}) + 9} = \frac{7}{9}$

$\Rightarrow \frac{28 x - 21}{20 x + 21} = \frac{7}{9}$

$\Rightarrow x = 3$

So, the can contained 21 litres of A.

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Filed Under: Alligation or Mixture

272 47396

Q:

A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

A) 136	B) 236
C) 336	D) 436

Answer & Explanation Answer: C) 336

Explanation:

let ABCD be the given parallelogram

area of parallelogram ABCD = 2 x (area of triangle ABC)

now a = 30m, b = 14m and c = 40m

s=1/2 x (30+14+40) = 42

Area of triangle ABC = $\sqrt{[s (s - a) (s - b) (s - c)]}$

= $\sqrt{[42 (12) (28) (2)]}$ = 168sq m

area of parallelogram ABCD = 2 x 168 = 336 sq m

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

103 47238

Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 20%	B) 30%
C) 40%	D) 50%

Answer & Explanation Answer: D) 50%

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x/2 and New breadth=3y

New area = $\frac{3}{2} x y$

Therefore, Increase in area = New area-original area = $\frac{3}{2} x y - x y = \frac{1}{2} x y$

Therefore, Increase % = $\frac{i n c r e a s e i n a r e a}{o r i g i n a l a r e a} * 100 = (\frac{\frac{1}{2} x y}{x y}) * 100 = 50$ %

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

47 47198

Q:

What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?

A) 23	B) 31
C) 29	D) 37

Answer & Explanation Answer: C) 29

Explanation:

87)13601(156
87
-----
490
435
-----
551
522
-----
29
-----
Required number is 29.

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Filed Under: Numbers

195 47110

Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

Answer

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.

So, 5 years ago, as the ratio of their ages was 5 : 7, we can write (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

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Subject: Problems on Ages

209 47035

Quantitative Aptitude - Arithmetic Ability Questions

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